The right option is (c). The Mean Value Theorem does not apply since f(x) is not differentiable on (-1,8). Because the derivative of f is 2/3 x^(-1/3) which is undefined at x=0.So, that would imply that it is not differentiable along the interval.
Step-by-step explanation:





Answer:
4
Step-by-step explanation:
7+(-14)+(-6)+13+4
7+(-20)+13+4
(-13)+13+4
0+4
4
F(x) = -6(1.02)^x has a y-intercept at f(x) = -6(1.02)^0
f(x) = -6(1)
f(x) = -6
f(x) has a y-intercept at (0, -6)
g(x) has a y-intercept at (0, -3)
Therefore, the y-intercept of f(x) is equal to 2 times the y-intercept of g(x).