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1 year ago

I need help with this

Mathematics

1 answer:

JulsSmile [24]1 year ago

3 0

The value of the x from the given equation is 1 and 6/7.

According to the statement

we have given that the quadratic equation and we have to find the solve for the value of the x.

So, For this purpose we know that the

A quadratic equation is any equation that can be rearranged in standard form as where x represents an unknown, and a, b, and c represent known numbers.

So, The given equation is

7x^2 -x -6 =0

Find the factors of the equation

7x^2 -7x + 6x -6 =0

7x(x-1) -6(x-1) = 0

(x-1)(7x-6) =0

here the values of x becomes 1 and 6/7.

So, The value of the x from the given equation is 1 and 6/7.

Learn more about quadratic equation here

brainly.com/question/25841119

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Un triángulo rectángulo tiene un área de 84 pies2 y una hipotenusa de 25 pies de largo. ¿Cuáles son las longitudes de sus otros

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Step-by-step explanation:

In the right triangle, the hypotenuse is 25 feet long. The area of this triangle is 84 square feet.

Let x feet and y feet be the lengths of triangle's legs.

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The area of the right triangle is half the product of its legs, thus

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Solve the system of two equations:

$\left\{\begin{array}{l}x^2+y^2=625\\ \\xy=168\end{array}\right.$

From the second equation:

$x=\dfrac{168}{y}$

Substitute it into the first equation:

$\left(\dfrac{168}{y}\right)^2+y^2=625\\ \\168^2+y^4=625y^2\\ \\y^4-625y^2+168^2=0\\ \\D=(-625)^2-4\cdot 168^2=(625-2\cdot 168)(625+2\cdot 168)=289\cdot 961=17^2\cdot 31\\ \\\sqrt{D}=17\cdot 31=527\\ \\y^2_{1,2}=\dfrac{-(-625)\pm 527}{2}=49,\ 576\\ \\y_1=7,\ y_2=-7,\ y_3=24,\ y_4=-24$

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