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Arada [10]
3 years ago
15

Find the slant height of this square pyramid.

Mathematics
2 answers:
Leno4ka [110]3 years ago
7 0

Answer:

3\sqrt{3}

Step-by-step explanation:

On the attached diagram, the slant height is denoted as s. In your case, the height s is the height of the equilateral  triangle with side 6.

The height of the equilateral triangle with side a can be calculated as

s=\dfrac{a\sqrt{3}}{2}.

Thus,

s=\dfrac{6\sqrt{3}}{2}=3\sqrt{3}.

Serga [27]3 years ago
3 0

Answer:

<h2>3√3 in</h2>

Step-by-step explanation:

The lateral side is the equilateral triangle.

The formula of a height of an equilateral triangle with the sides <em>a</em>

h=\dfrac{a\sqrt3}{2}

We have <em>a = 6 in</em>.

Substitute:

h=\dfrac{6\sqrt3}{2}=3\sqrt3

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In a school,3/5 of the pupils were boys and there were 240 girls. How many boys were in the school.
zepelin [54]

Answer:

If 2/5 is 240 then 1/5 is 120..multiply 120 by 5 which is 600 so...

600=total

Then..multiply 120 by 3 which will give the 3/5 boys which is 360 so...

360 boys

Step-by-step explanation:

8 0
2 years ago
Find the area of the rectangle
Hunter-Best [27]

Answer:

<h2>Option A = 1*3 = 3 unit² </h2>

area \: of \: rectangle \:  = length \:  \times breath

length \:  = distance \: between \: f \: and \: g \: or \: between \: e \: and \: h \:

<h3>Distance between f and G = distance between E and H </h3>

F = (3,7)

G = (6,4)

H = (5,3)

E= (2,6)

= (3 units)

<h3>Distance between FE = GH </h3>

= 1 units

Area = 3* 1

= 3 units²

5 0
2 years ago
Six friends earned $645 for painting some rooms in a neighbors house. If they divide the money equally, how much will each frien
raketka [301]
Each friend would get $107.5
7 0
3 years ago
Quiz scores of statistics students were obtained by a teacher and listed below. Construct a frequency distribution beginning wit
DanielleElmas [232]

Answer:

The frequency distribution is

The frequency distribution is

S/N Class limit Frequency

1 0-2 4

2 3 -4 1

3 5-6 2

4 7-8 2

5 9 - 10 0

6 11 - 12 0

The value for value upper class boundary of the fifth class is CB_5 =  10.5

Step-by-step explanation:

From the question we are told that

The lower class limit is 0

The class width is 2

The scores is 8,6,2,4,2,0,2,6,7

The frequency distribution is

S/N Class limit Frequency

1 0-2 4

2 3 -4 1

3 5-6 2

4 7-8 2

5 9 - 10 0

6 11 - 12 0

Generally the upper class boundary of the fifth class is mathematically represented as

CB_5 =  \frac{10 + 11}{2}

            CB_5 =  10.5

8 0
3 years ago
What is the following quotient? StartFraction StartRoot 96 EndRoot Over StartRoot 8 EndRoot
steposvetlana [31]

Answer:

D 12

Step-by-step explanation:

because your just solving 96/8

3 0
2 years ago
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