Answer: 4010 mol of iron atoms
Explanation:
<u>Given Information</u>
Iron Oxide = Fe₂O₃
Mass = 320 kg
<u>Given atomic mass / molecular weight</u>
Fe = 55.8 g / mol
O = 16.0 g / mol
Fe₂O₃ = 55.8 × 2 + 16.0 × 3 = 159.6 g / mol
<u>Given formula</u>
n = m / M
- n = number of moles
- m = mass
- M = molecular weight
<u>Convert the unit of mass to Gram</u>
1 kg = 1000 g
320 kg = 320 × 1000 = 320 000 g
<u>Substitute values into the given formula</u>
n = m / M
n = (320000) / (159.6)
n ≈ 2005 mol of Fe₂O₃
<u>Calculate the number of moles of Fe (Iron atoms)</u>
Since each mole of Fe₂O₃ has 2 moles of Fe, then:
2005 × 2 =
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