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tamaranim1 [39]
3 years ago
8

Given the balanced equation representing a reaction at 101.3 kPa and 298 K:

Chemistry
1 answer:
ser-zykov [4K]3 years ago
8 0
Answer (4)

Endothermic processes: are those in which occurs the absorption of heat.
the change of enthalpy (ΔH) is greater <span>than zero.
</span>
hope this helps!
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How can i prove that nascent oxygen more reactive than normal oxygen ?
laila [671]
Nascent oxygen has much higher reactivity than the oxygen bubbled through the reaction mixture. It doesn't stay nascent for long (you are right about it being converted quick to just O2), which is why it has to be generated in situ
6 0
3 years ago
a skateboarder wants to skate down the ramp at a skate park he will want the forces acting on him to be
kvasek [131]

Answer:

increase

Explanation:

At the skate park when a skateboarder wants to skate down a ramp, the skate boarder wishes to move faster and with speed so that it help him to skate more time. This can only be achieved if the all the forces acting on him will increase as he skates down the ramp without much of the frictional force acting on the wheels of the skate board. The less friction force acts on the wheel, the more he can skate with more speed.

Thus, the skateboarder wants the force to be increase that is acting on him.

4 0
3 years ago
How many moles of ammonia (nh3 will be produced from 4.0 moles of nitrogen (n2?
Lana71 [14]
Standard equation would be N2(g)+3H2(g)==>2NH3(g), so through stoichiometry, (4 mol N2)(2mol NH3/1 mol N2), assuming excess H2, would yield 8 moles of NH3.  
3 0
3 years ago
45.3 in. to millimeters
Stels [109]

1,150.62 millimeters

8 0
3 years ago
In an experiment, a student needs 250.0 mL of a 0.100 M copper (II) chloride solution. A stock solution of 2.00 M copper (II) ch
LekaFEV [45]

Answer : The volume of stock solution needed are, 12.5 mL

Explanation :

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the initial molarity and volume of copper (II) chloride.

M_2\text{ and }V_2 are the final molarity and volume of stock solution of copper (II) chloride.

We are given:

M_1=0.100M\\V_1=250.0mL\\M_2=2.00M\\V_2=?

Putting values in above equation, we get:

0.100M\times 250.0mL=2.00M\times V_2\\\\V_2=12.5mL

Hence, the volume of stock solution needed are, 12.5 mL

8 0
3 years ago
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