Answer:
[HI] = 0.097 M
Explanation:
Let's consider the following reaction.
2 HI(g) ⇄ H₂(g) + I₂(g)
The order of reaction for HI is 1. Thus, we can calculate the concentration of HI ([HI]) at certain time using the following expression:
ln [HI] = ln [HI]₀ - k. t
where,
[HI]₀ is the initial concentration of HI
k is the rate constant
t is the time elapsed
When [HI]₀ = 0.440 M and t = 0.210 s, the concentration of HI is
ln [HI] = ln (0.440) - 7.21 s⁻¹ × 0.210 s
ln [HI] = -2.33
[HI] = 0.097 M
Answer : The time passed in days is 28.6 days.
Explanation :
Half-life = 14.3 days
First we have to calculate the rate constant, we use the formula :
Now we have to calculate the time passed.
Expression for rate law for first order kinetics is given by:
where,
k = rate constant =
t = time passed by the sample = ?
a = let initial amount of the reactant = 100 g
a - x = amount left after decay process = 100 - 75.0 = 25.0 g
Now put all the given values in above equation, we get
Therefore, the time passed in days is 28.6 days.
Answer:
The partial pressure of bar.
Explanation:
Given:
Volume L
Total pressure bar
Temperature of system K
Moles of nitrogen mole
Partial pressure bar
From ideal gas equation,
Where = gas constant
First finding partial pressure of nitrogen
bar
We know, total pressure is given by
bar
Therefore, the partial pressure of bar.
Answer:
CaCO3+2HCl=CaCl2+H2O+CO2 this is the balanced reaction occur between calcium carbonate and HCl to minimize the hyperacidity.
Explanation:
CaCO3 reacts with hydrochloric acid produced by oxytonic cells of the stomach to generate calcium chloride (CaCl2) and water(H2O) along with the release of carbon dioxide(CO2) gas.
This reaction helps to minimize hyperacidity.