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Alekssandra [29.7K]
1 year ago
10

The ability of Salmonella to produce H2S is one characteristic that helps differentiate it from Shigella.

Biology
1 answer:
Goryan [66]1 year ago
7 0

KIA tubes and SIM tube in this exercise to determine whether or not your unknown produced H2S.

<h3>What gas is produced by Salmonella?</h3>

F0F1 ATP synthase activity is necessary for Salmonella typhimurium to produce hydrogen sulfide and fermentative gases.

<h3>H2S production by Salmonella enterica?</h3>

Infections with Salmonella enterica continue to have a serious impact on global public health. H2S-negative Salmonella have lately surfaced, despite the fact that the capacity of S. enterica to produce H2S is an essential phenotypic trait utilized to screen and identify Salmonella with selective media.

<h3>H2S is it produced by Shigella?</h3>

Shigella do not create H2S, hence colonies on Hektoen agar appear bluish-green rather than having the black center seen with Salmonella. Shigella are comparatively biochemically inactive and do not ferment lactose or xylose.

learn more about Salmonella here

<u>brainly.com/question/14326716</u>

#SPJ4

the question you are looking for is

The ability of Salmonella to produce H2S is one characteristic that helps differentiate it from Shigella. List the three opportunities you had in this exercise to determine whether or not your unknown produced H2S.

KIA tubes and SIM tube

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When a BB male and a Bb female are crossed, 50% BB and 50% Bb genotypes are produced and a 100% black phenotype.

The entire number of genes that an organism receives from its parents makes up its genotype. Alleles, which are pairs of these genes, are found. One gene is dominant and one gene is recessive in each allele.

The dominant gene is always expressed in a cross if it is present. Only when a pair of alleles is made up of two recessive genes does the recessive gene express itself. In this instance, the white fur is subordinate to the black fur. White fur is represented as b, while black fur is represented as B.

We can see that when we cross the BB male and Bb female, we will get a genotype that is 50% BB and 50% Bb, as well as a phenotype that is 100% black fur.

Parents: BB x Bb

Gametes: B, B, and B, b

Offspring: BB, BB, Bb, Bb

The genotypic ratio = 1:1

The phenotypic ratio = 1:0

Genotype probabilities:

P(BB) = 2/4 = 0.5 or 50%

P(Bb) = 2/4 = 0.5 or 50%

Learn more about genotype here:

brainly.com/question/18101683

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