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DaniilM [7]
3 years ago
13

What are the benefits of automating a process? Choose all that apply.

Computers and Technology
1 answer:
taurus [48]3 years ago
3 0

Answer:

All except It makes a company look modern.  

Explanation:

You might be interested in
Write a static method named anglePairs that accepts three angles (integers), measured in degrees, as parameters and returns whet
padilas [110]

Answer:

The java program for the scenario is given below.  

import java.util.*;

public class Test

{

// method returning sum of all digits in the integer parameter

static boolean anglePairs(int a1, int a2, int a3)

{

   // variable to hold sum of two complementary angles

   int comp=90;  

   // variable to hold sum of two supplementary angles

   int supp=180;

   // boolean variable to hold result

   boolean result = false;

   if( (a1+a2 == comp) || (a2+a3 == comp) || (a1+a3 == comp) )

   {

       if( (a1+a2 == supp) || (a2+a3 == supp) || (a1+a3 == supp) )

           result = true;

       else

           result = false;

   }    

           // return variable result

       return result;

}

public static void main(String[] args)

{

   // method is called by passing three positive angles

   System.out.println("The pair of angles have both complementary and supplementary angles " + anglePairs(100, 80, 90) );    

}

}

OUTPUT

The pair of angles have both complementary and supplementary angles false

Explanation:

The program works as described below.

1. The method, anglePairs(), is declared as static having return type as Boolean which takes three positive integer parameters.

static boolean anglePairs(int a1, int a2, int a3)

{

}

2. The integer variable, comp, is declared and initialized to 90.

3. The integer variable, supp, is declared and initialized to 180.

4. The Boolean variable, result, is declared and initialized to false.

5. Using if-else statements, sum of two angles are compared with the variables, comp and supp.

6. If the sum of any two angles match with both, comp and supp, variables, the Boolean variable, result is assigned value true. Otherwise, result is assigned value false.

7. The value of result is returned.

8. Inside main() method, the function anglePairs() is called and three positive numerical values are passed as parameters.  The output is displayed.

9. All the above code is written inside the class Test.

10. User input is not taken since it is not mentioned in the question.

8 0
3 years ago
If you need to provide a storage server with fault tolerance through the use of multiple paths between the server and the actual
yan [13]

Answer:

The correct answer to the following question will be "Multipath I/O ".

Explanation:

Multipath I/O going to minimize the impact of a failure of either the host network interface by offering an alternative access route through storage media as well as a Windows OS.

  • It offers the possibility for someone like you to support high accessibility and significantly improve efficiency based on your SAN setup.
  • Offer valuable even fault resistance to a terminal server by using different objectives or paths.

So, you should install this Multipath I/O.

3 0
3 years ago
Please help me with these two questions! 60 points!
RUDIKE [14]

Answer:

Networks prevent unauthorized access to data and protect equipment. Networked computers are less likely than single computers to suffer equipment failure. Networks allow computers to connect quickly and to share data or equipment.

Explanation:

3 0
3 years ago
Discussion Topic:
hodyreva [135]

Answer:

Prevents lagging

Explanation:

This prevents the website from being slow and upto shape so those who access it dont have difficulties

7 0
2 years ago
CODING TIME
Fynjy0 [20]

Answer:

food_list = ['rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea']

one_more = ['meat']

extend_list = food_list + one_more

print(extend_list)

Output : ['rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea', 'meat']

food_list.append('milk')

print(food_list)

Output : ['rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea', 'milk']

food_list.insert(0, 'cake')

print(food_list)

Output : ['cake', 'rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea']

flowers = ['rose', 'hibiscus', 'lily']

flowers.remove('rose')

print(flowers)

Output : ['hibiscus', 'lily']

To remove rose using pop()

flowers.pop(0)

Explanation:

The + operator and append method adds elements to the end of an existing list item.

The insert method adds element at the specified index

Remove method deletes element by stating the name of the element to be deleted while pop deletes element using the index value of the element.

7 0
2 years ago
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