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Ad libitum [116K]
1 year ago
6

Bootes is a constellation found near __________________ -The Big Dipper -Orion -Taurus

Physics
1 answer:
Elden [556K]1 year ago
5 0

Answer:

The Big Dipper

Explanation:

Bootes is near the "Big Dipper" which is itself part of Ursa Major.

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A 12-V car battery supported a current of 150 mA to bulb calculate the power absorbed by the bulb over an interval of 20 mintues
ASHA 777 [7]

Answer:

  • +1.8W
  • 2,160J

Explanation:

First, we need to solve for the power absorbed by the bulb.

Formula [ p = vi ]

p = 12 * 150 * 10^-3

p = +1.8W

Second, we can solve for the power aborbed in a interval of 20 minutes.

Formula [ e = vit ]

e = 12 * 150 * 10^-3 * 20 * 60

e = 2,160J

Just a note that "20 * 60" represents the time given in seconds.

Best of Luck!

7 0
2 years ago
When a wave source moves toward a receiver, does the receiver encounter an increase in wave frequency, wave speed, or both?
NeX [460]

Answer:

<em>Increase in wave frequency only</em>

4 0
3 years ago
Which statement describes a chemical property related to the
valina [46]

Answer:

B. Iron is a good conductor of electricity because the metallic

bonds between its atoms allow electrons to move freely.

Explanation:

5 0
2 years ago
Consider a particle with initial velocity v⃗ that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.
lina2011 [118]

Answer:

-6.0 m/s, 10.4 m/s

Explanation:

To find the x- and y- components, we have to apply the formulas:

v_x = v cos \theta

v_y = v sin \theta

where

v = 12.0 m/s is the magnitude of the vector

\theta is the angle between the direction of the vector and the positive x-axis

Here, the angle given is the angle above the negative x-axis; this means that the angle with respect to the positive x-axis is

\theta=180^{\circ} - 60^{\circ} = 120^{\circ}

So, the two components are:

v_x = (12.0 m/s) cos 120^{\circ}=-6.0 m/s

v_y = (12.0 m/s) sin 120^{\circ}=10.4 m/s

5 0
3 years ago
A boat heads directly across a river. Its speed relative to the water is 2.6 m/s. It takes it 355 seconds to cross, but it ends
Zigmanuir [339]

Answer:

Vr = 3.24m/s

The boat is going 3.24m/s relative to the bank of the river.

Explanation:

The relative speed of the boat to the bank Vr is the resultant of speed of boat relative to the water Vb and the speed of boat as a result of the water current or wind Vw

Vr = √(Vb^2 + Vw^2) .....1

Given;

Vb = 2.6m/s

Vw = distance downstream/time = 690m/355s

Vw = 1.94m/s

From equation 1 above; substituting the values

Vr = √(2.6^2 + 1.94^2)

Vr = 3.24m/s

The boat is going 3.24m/s relative to the bank of the river.

7 0
3 years ago
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