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gizmo_the_mogwai [7]
4 years ago
9

Nick lives in area that has a south-facing slope. The temperature in his area is always high. Which of these abiotic factors is

responsible for high temperatures in Nick’s area?
A) nutrients
B) soil
C ) water
D) topography
Physics
2 answers:
Dimas [21]4 years ago
4 0
<span>D) topography is the answer  
</span><span />
navik [9.2K]4 years ago
3 0

Answer : (D) topography

Explanation :

Nick lives in an area that has a south-facing slope. The temperature in his area is always high. This implies that Nick's place gets maximum sun rays.

Abiotic factors are the things or the conditions which affect our ecosystem or organisms in it.

Topography means the full description of any place. It is the study of the properties of land surfaces. So, the topography is responsible for high temperatures in Nick’s area

Out of the given options, correct one is (D) "topography".

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The potential difference between the plates will therefore likewise decrease if the distance between the plates is reduced, we will state in this case.

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3 years ago
If a runner exerts 457 j of work to make 321 w of power then how long did it take the runner to do the work
MA_775_DIABLO [31]

The time taken by the runner to do the work is 1.42 seconds.

Given the data in the question;

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  • Power; P = 321W
  • Time elapsed; t = \ ?

<h3>Power</h3>

Power can be simply referred to as the quantity of energy transferred per unit time.

It is expressed as;

P = \frac{W}{t}

Where W is work done and t is time elapsed.

To determine the time it took the runner to do the work, we substitute our given values into the expression above.

P = \frac{W}{t} \\\\t = \frac{W}{P} \\\\t = \frac{457J}{321W} \\\\t = \frac{457 kgm^2/s^2}{321 kgm^2/s^3}\\\\t = 1.42s

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5 0
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Ship A is located 4.2 km north and 2.7 km east of ship B. Ship A has a velocity of 22 km/h toward the south and ship B has a vel
kotykmax [81]

Answer:

(a) The x-component of velocity is 31.55 km/h

(b) The y-component of velocity is 44.92 km/hr

Solution:

As per the solution:

The relative position of ship A relative to ship B is 4.2 km north and 2.7 km east.

Velocity of ship A, \vec{u_{A}} = 22 km/h towards South = - 22\hat{j}

Velocity of ship B, \vec{u_{B}} = 39 km/h Towards North east at an angle of 36^{\circ} = \vec{u_{B}} = 39sin36^{\circ} \hat{j}

Now, the velocity of ship A relative to ship B:

\vec{u_{AB}} = \vec{u_{A}} - \vec{u_{B}}

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Now,

\vec{u_{AB}} = - 22\hat{j} +39cos36^{\circ} \hat{i} - 39sin36^{\circ} \hat{j}

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4 0
3 years ago
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Answer:

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