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gizmo_the_mogwai [7]
3 years ago
9

Nick lives in area that has a south-facing slope. The temperature in his area is always high. Which of these abiotic factors is

responsible for high temperatures in Nick’s area?
A) nutrients
B) soil
C ) water
D) topography
Physics
2 answers:
Dimas [21]3 years ago
4 0
<span>D) topography is the answer  
</span><span />
navik [9.2K]3 years ago
3 0

Answer : (D) topography

Explanation :

Nick lives in an area that has a south-facing slope. The temperature in his area is always high. This implies that Nick's place gets maximum sun rays.

Abiotic factors are the things or the conditions which affect our ecosystem or organisms in it.

Topography means the full description of any place. It is the study of the properties of land surfaces. So, the topography is responsible for high temperatures in Nick’s area

Out of the given options, correct one is (D) "topography".

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harkovskaia [24]

Answer:

500 watts

Explanation:

Recall that the definition of power is the amount of energy delivered per unit of time.

In our case, the energy delivered is potential energy which we can estimate as the product of the weight of the object times the distance it is lifted above ground:

200 N x 10 m = 2000  Nm

then the power is the quotient of this potential energy divided the time it took to lift the object to that position:

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A sinusoidal sound wave moves through a medium and is described by the displacement wave function
ZanzabumX [31]

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the wavenumber and angular speed of the wave equation can be determined respectively by

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From the question above, we know that:

y = 2.00cos (15.7x - 858t)

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4 0
1 year ago
The flagpole is held vertical by two ropes. The first of these ropes has a tension in it of 100 N and is at an angle of 60° to t
KatRina [158]

Answer:

T₂ = 123.9 N,  θ = 66.2º

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X axis

       T₁ₓ - T_{2x} = 0

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Y axis y

      T_{1y} + T_{2y} - 200N = 0

      T_{2y} = 200 -T_{1y}

let's use trigonometry to find the component of the stresses

         sin 60 = T_{1y} / T₁

         cos 60 = t₁ₓ / T₁

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         T1x = T₁ cos 60

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for voltage 2 it is done in the same way

         T_{2y} = T₂ sin θ

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           T₂ sin θ= 200 - 86.6 = 113.4

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           tan θ = 113.4 / 50

           θ = tan⁻¹ 2,268

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we caption in equation 1

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           T₂ = 50 / cos 66.2

           T₂ = 123.9 N

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