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fredd [130]
2 years ago
12

A 12-V car battery supported a current of 150 mA to bulb calculate the power absorbed by the bulb over an interval of 20 mintues

?
Physics
1 answer:
ASHA 777 [7]2 years ago
7 0

Answer:

  • +1.8W
  • 2,160J

Explanation:

First, we need to solve for the power absorbed by the bulb.

Formula [ p = vi ]

p = 12 * 150 * 10^-3

p = +1.8W

Second, we can solve for the power aborbed in a interval of 20 minutes.

Formula [ e = vit ]

e = 12 * 150 * 10^-3 * 20 * 60

e = 2,160J

Just a note that "20 * 60" represents the time given in seconds.

Best of Luck!

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A street light is mounted at the top of a 15-ft-tall pole. a man 6 ft tall walks away from the pole with a speed of 4 ft/s along
Arlecino [84]

Answer: 2.67 ft/s



Explanation:



1) The diagram with the triangle that represents the situation is in the image attached.


2) Similarity properties


(x + y) / 15 = y/6


⇒ 6(x+y) = 15y


⇒ 6x + 6y = 15y


⇒ 6x = 15y - 6y


⇒ 6x = 9y


⇒ y = 6x / 9


⇒ y = 2x / 3


3) Velocity is the derivative respecto to time. Then, find the derivative respect to time, t, on both sides


dy/dt = (2/3)dx/dt


4) The statement tells v = dx/dt = 4 ft/s


⇒ dy/dt = (2/3) 4 ft/s = (8/3)m/s ≈ 2.67 ft/s


Notice that this speed is constant, it does not depends upon the distance of 30 ft.

5 0
3 years ago
What is the potential energy of a 30 kg object that is 10 meters up on a ladder?
scZoUnD [109]

Answer:

<h2>3000 J</h2>

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 30 × 10 × 10

We have the final answer as

<h3>3000 J</h3>

Hope this helps you

3 0
3 years ago
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