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fredd [130]
2 years ago
12

A 12-V car battery supported a current of 150 mA to bulb calculate the power absorbed by the bulb over an interval of 20 mintues

?
Physics
1 answer:
ASHA 777 [7]2 years ago
7 0

Answer:

  • +1.8W
  • 2,160J

Explanation:

First, we need to solve for the power absorbed by the bulb.

Formula [ p = vi ]

p = 12 * 150 * 10^-3

p = +1.8W

Second, we can solve for the power aborbed in a interval of 20 minutes.

Formula [ e = vit ]

e = 12 * 150 * 10^-3 * 20 * 60

e = 2,160J

Just a note that "20 * 60" represents the time given in seconds.

Best of Luck!

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An oscillating pendulum, or anything else in nature that involves "simple harmonic" (sinusoidal) motion, spends 1/4 of its period going from zero speed to maximum speed, and another 1/4 going from maximum speed to zero speed again, etc. After four quarter-periods it is back where it started.

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The following is the longitudinal characteristic equation for an F-89 flying at 20,000 feet at Mach 0.638. The Short Period natu
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hello your question is incomplete  attached below is the missing part  

answer : short period oscillations frequency  = 0.063 rad / sec

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Explanation:

first we have to state the general form of the equation

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