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Gwar [14]
3 years ago
7

A sonar wave is reflected from the ocean floor. For which angles of incidence do the wave’s angle of reflection equal its angle

of incidence?
Physics
1 answer:
nadya68 [22]3 years ago
7 0
After a thorough research, there exists the same question that has the following choices.

<span>(1) angles less than 45°, only
(2) an angle of 45°, only
(3) angles greater than 45°, only
<span>(4) all angles of incidence

The correct answer (4) all angles of incidence.</span></span>
You might be interested in
A sound wave travels at 379 m/sec and has a wavelength of 8 meters. Calculate its frequency and period.
olga nikolaevna [1]

\qquad\qquad\huge\underline{{\sf Answer}}

Wavelength, Wavespeed and frequency depends on each other in the following way :

\qquad \sf  \dashrightarrow \: frequency =  \dfrac{wave \:  \: velocity}{wavelength}

\qquad \sf  \dashrightarrow \: f =  \dfrac{389}{8}

\qquad \sf  \dashrightarrow \: f \approx 48.62 \:  \: hertz

And we know the Reciprocal relationship between frequency and period ~

So, let's find it's period •

\sf{\qquad \sf  \dashrightarrow \: t = \dfrac{8}{389}}

\sf{\qquad \sf  \dashrightarrow \: t \approx 0.02 sec }

6 0
2 years ago
Suppose you wanted to break a meter stick over your knee. The cross-section of a meter stick is rectangular. Will it be easier t
LenaWriter [7]

Answer:

It will be easier to break the meter rule with the long side against my knee.

Explanation:

To break the meter rule involves the principle of bending moment. The long side will require less force to generate the same amount of bending moment that will have to be generated to break the meter rule. The short side on the other hand will require more force to generate this mount of bending moment. This is because the shorter has a very small surface area, which concentrates the force on your knee. The pressure is then dissipated as more pressure to your knee. Th longer side has a lesser surface area so, most of the force is used in breaking the meter rule.  

6 0
3 years ago
red light from a He-Ne laser is at 590.5 nm in the air. it is fired at an angle of 31.0 to horizontal at a flat transparent crys
Darina [25.2K]

Answer:

7374.4

Explanation:

I took the test

(filler so I can post)

5 0
2 years ago
How much charge is on each plate of a 3.00-μF capacitor when it is connected toa 15.0-V battery? b) If this same capacitor is c
Sauron [17]

Answer:

(a) 45 micro coulomb

(b) 6 micro Coulomb

Explanation:

C = 3 micro Farad = 3 x 10^-6 Farad

V = 15 V

(a) q = C x V

where, q be the charge.

q = 3 x 10^-6 x 15 = 45 x 10^-6 C = 45 micro coulomb

(b)

V = 2 V, C = 3 micro Farad = 3 x 10^-6 Farad

q = C x V

where, q be the charge.

q = 3 x 10^-6 x 2 = 6 x 10^-6 C = 6 micro coulomb

6 0
3 years ago
A 1.2 L weather balloon on the ground has a temperature of 25°C and is at atmospheric pressure (1.0 atm). When it rises to an el
Irina-Kira [14]

Answer:

71.19 C

Explanation:

25C = 25 + 273 = 298 K

Applying the ideal gas equation we have

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

where P, V and T are the pressure, volume and temperature of the gas at 1st and 2nd stage, respectively. We can solve for the temperature and the 2nd stage:

T_2 = T_1\frac{P_2V_2}{P_1V_1} = 298\frac{0.77*1.8}{1.2*1} = 298*1.155 = 344.19 K = 344.19 - 273 = 71.19 C

4 0
3 years ago
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