I believe the answer would be Draft Quality. (300x300 resolution).
Answer:
#include <iostream>
#include <time.h>
#include <string>
using namespace std;
int main(){
srand(time(NULL));
cout<<"Throw dice"<<endl;
int b =0;
int a=0;
a=rand()%6;
b=rand()%6;
for (int i =0;i<1;i++)
{cout<<"dice one: "<<a<<endl;}
for (int i =0;i<1;i++)
{cout<<"dice two: "<<b<<endl;}
if(a>b)
{cout<<"first dice won"<<endl;}
if(b>a)
{cout<<"second dice won"<<endl;}
else{cout<<"they are same"<<endl;
return main();
}
return 0;
}
Explanation:
/*maybe it help you it is almost done*/
Answer:
def length( mystring):
count = 0
for i in mystring:
count += 1
return count
def reversed( mystring):
strlist = []
for i in range(length(mystring)):
strlist.append(mystring[(length(mystring) - 1) - i])
txt = "".join(strlist)
return txt
string = 'Yolanda'
print(reversed(string))
Explanation:
The python module defines two functions 'reversed' and 'length'. The length function counts the number of characters in a string variable while the reversed function reverses the string variable value.
Answer:
Below is the required code:
Explanation:
SELECT Product_Finish AS "Desk Finish",
avg(Standard_Price) AS "Average Price"
FROM Product_T
WHERE "Average Price">200
ORDER BY "Average Price" DESC;
Answer:
<em>Locality of reference.</em>
Explanation:
In computing, The principle of locality of reference is the probability of a processor to repeatedly access the same set of memory locations within a small time interval. This reference of locality can be spatially based (repetitive usage of data within the same location on the computer memory), or temporally based (repetitive usage of a particular data or resources within a shot time interval). The ability of some computing system to perform this action increases their predictability, and efficiency of memory hierarchy use, among other abilities.
