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dangina [55]
3 years ago
15

42 students arrived at the school dance after it started. in all 78 students attended. write and solve an equation to find how m

any students arrived at the dance before it started. plz help right when you see it!!!
Mathematics
1 answer:
vladimir2022 [97]3 years ago
6 0

Answer:

The answer is 36

Step-by-step explanation:

we know 42 students arrived after the dance started and 78 arrived in total. You have to subtract 42 from 78. how I remember this: part+part=whole whole-part=part

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A grocer bought n eggs at $x each. He marked up the price of each egg by $y and sold all of them. Find the sales amount, express
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Answer:

Sales = n \times ($x + $y)

Step-by-step explanation:

The basic simple sales equation is

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Here in the given question,

Total quantity of sales = n

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(Markup refers to the profit added to cost)

Thus price = $x (cost) + $y (markup)

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Step-by-step explanation:

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Aleks [24]

Answer: 277 ways

Step-by-step explanation:

Let’s start bycreating 10-unit pieces using the 4-unit piece.

The arrangements are:

1). 4-3-3 (3 permutations)

2). 4-3-2-1 = 4! = 24 permutations.

3). 4-3-1-1-1 (5*[4!/(3!1!)]

= 5*4

= 20permutations

4). 4-2-2-2 (4 permutations)

5). 4-2-2-1-1 (5 *[4!/(2!2!)]

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6). 4-2-1-1-1-1(6*[5!/(4!1!)]

= 6*5

= 30 permutations

Let’s-consider the arrangements using one or more3-unit pieces and no 4-unit piece:

7). 3-3-2-2 (4!/(2!2!)

8). 3-3-2-1-1 (5*(4!/(2!2!)

= 5*6

= 30 permutations.

9). 3-3-1-1-1-1 (6!/(4!2!) = 0

10). 3-2-2-2-1 (5*4!/(3!1!)

= 5*4

= 20permutations

11). 3-2-2-1-1-1 (6*5!/(3!2!)

= 6*10

= 60 permutations

Finally we would look at the arrangements using only 1-and 2-unit pieces:

12). 2-2-2-1-1-1-1 (7!/(4!3!)

= 35 permutations

add them all up:

(3 + 24 + 20 + 4) + (30 + 30 + 6 + 30) + (15 + 20 + 60 + 35)

=51 + 96 + 130

= 277ways

5 0
2 years ago
When a dice is rolled find the probability of getting a number less than or equal to 6
Dahasolnce [82]

Answer:

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Answer:

See attached graph

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