Um well KCF stands for Keep Change Flip which is used for dividing fractions... ask if you need a better description ☺️
Answer:
a) dx/dt = kx*(M - h/k - x)
Step-by-step explanation:
Given:
- The harvest differential Equation is:
dx/dt = kx*(M-x)
Suppose that we modify our harvesting. That is we will only harvest an amount proportional to current population.In other words we harvest hx per unit of time for some h > 0
Find:
a) Construct the differential equation.
b) Show that if kM > h, then the equation is still logistic.
c) What happens when kM < h?
Solution:
- The logistic equation with harvesting that is proportional to population is:
dx/dt = kx*(M-x) hx
It can be simplified to:
dx/dt = kx*(M - h/k - x)
- If kM > h, then we can introduce M_n=M -h/k >0, so that:
dx/dt = kx*(M_n - x)
Hence, This equation is logistic because M_n >0
- If kM < h, then M_n <0. There are two critical points x= 0 and x = M_n < 0. Since, kx*(M_n - x) < 0 for all x<0 then the population will tend to zero for all initial conditions
Answer:
900,000
Step-by-step explanation:
Round 500 and above so round up to 900,000.
Hope this helps plz hit the crown :D
1/2 (14x-2)-1/4(4x-24) = 6x + 5
Answer:
hello : 5/8; 65/100 ; 2/3 ; 7/10
Step-by-step explanation:
lcm: (least common divisor) for : 3 ; 10 ; 8 ; 100 is 600
2/3 = (2×200)/(3×200) = 400 /600
7/10 = (7×60)/(10×60) = 420 /600
5/8 = (5×75)/(8×75) = 375 /600
65/100 = (65×6)/(100×6) = 390 /600
the order of these fractions from least to greatest is:
5/8 ; 65/100 ; 2/3 ; 7/10
