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3 years ago

What 3 digits are in the units period?

Mathematics

1 answer:

Leto [7]3 years ago

8 0

Would it be the hundreds?

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Grocery store sells tangerines in 2/5 kg bags. A customer bought 4kg of tangerines for a school party. How many bags did he buy

Rama09 [41]

In order to have 4 kg, he must have 20/5 kg. Each bag is 2/5 kg, so 2/5 times 10 is 20/5 or 4kg. Therefore, he bought 10 bags of tangerines for the school party.

6 0

3 years ago

Can someone please help me with this question? Thank you!!!

EleoNora [17]

B, since 13 ppl have 2 or less TVs while 12 have 3 or more

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3 years ago

TRUE OR FALSE QUESTION

stira [4]

That's false. p(x) can have any number of linear factors (one or more).

p(x) = x(x+1)(x+2)(x+3)

has p(-3)=0 and four linear factors.

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4 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

4 years ago

2-2x2-(39 divided by 1)+2+9

artcher [175]

-30 is the answer for your question

6 0

3 years ago