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1 year ago

A softball needs to hit a bucket 43. 0 m away on flat ground. if it is aimed at 72. 0, what must its inital velocity be?

Physics

1 answer:

ddd [48]1 year ago

3 0

Answer:

This can easily be solved using the "range" formula

R = V0^2 * sin 2θ / g

V0^2 = g R / sin 2θ = 9.80 * 43 / sin 144 = 717 m^2/s^2

V0 = 26.8 m/s

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A 56.6-kg crate rests on a level floor at a shipping dock. The coefficients of static and kinetic friction are 0.517 and 0.260,

kifflom [539]

Answer:

Explanation:

Magnitude of frictional force = μ mg

μ is either static or kinetic friction.

To start the crate moving , static friction is calculated .

a ) To start crate moving , force required = μ mg where μ is coefficient of static friction .

force required =.517 x 56.6 x 9.8 = 286.76 N .

b ) to slide the crate across the dock at a constant speed , force required

= μ mg where μ is coefficient of kinetic friction , where μ is kinetic friction

= .26 x 56.6 x 9.8 = 144.21 N .

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3 years ago

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mariarad [96]

The answer should be:

Angle Of incidence is equal to angle of reflection.

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4 years ago

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EleoNora [17]

Answer:

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Explanation:

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4 years ago

Zeros are always considered significant digits when they are to the left of the decimal point

maksim [4K]

Answer:

Zeros to the left of a decimal can be insignificant place holders, such as in 0.043 (two significant figures).

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4 years ago

The Earth is approximately 150 million kilometers away from the Sun. If light travels at a speed of approximately 300,000 kilome

evablogger [386]

The correct answer to the question is 8.33 minutes.

CALCULATION:

The distance of earth from sun s = 150 million km.

We know one million = 10 lakh = $10^6$

Also 1 km = $10^3\ m$

Hence, the distance s = $150\times 10^6\times 10^3\ m$

= $15\times 10^{10}\ m$

The speed of light c = 300,000 km per second

= $3\times 10^8\ m/s$

We are asked to calculate the time.

The time of the reaching earth is calculated as -

$time=\ \frac{distance}{velocity}$

$t=\ \frac{s}{c}$

$=\ \frac{15\times 10^{10}} {3\times 10^8}\ second$

$=\ 500\ seconds$

We know one minute = 60 second.

Hence, 500 seconds = $\frac{500}{60}\ minute$

= $8.33\ minute$ [ans]

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3 years ago

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