A 500 Kg load is lifted through a vertical height of 10m in 25s by a crane. Calculate the power of the crane
1 answer:
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Answer:
The speed is .
(a) is correct option.
Explanation:
Given that,
Potential difference
Speed
If it were accelerated instead
Potential difference
We need to calculate the speed
Using formula of initial work done on proton
We know that,
Put the value into the formula
....(I)
If it were accelerated instead through a potential difference of , then it would gain a speed will be given as :
Using an above formula,
Put the value of
Hence, The speed is .
Answer:
120°
Explanation:
Draw a free body diagram. There are three forces acting on the traffic light. Two tension forces acting along the cables, and weight.
The tension forces have an angle θ between them. That means each tension force forms an angle of θ/2 with respect to the vertical. So the y component of each tension force is:
Ty = T cos (θ/2)
Sum of the forces in the y direction:
∑F = ma
Ty + Ty − W = 0
2 Ty = W
Substituting:
2 T cos (θ/2) = W
If W = T, then:
2 W cos (θ/2) = W
2 cos (θ/2) = 1
cos (θ/2) = 1/2
θ/2 = 60°
θ = 120°
