All categories

4 years ago

6x + 12 -3x =51. Step by step

1 answer:

8 0

Start by combing like terms. You will get 3x+12=51. Now subtract 12 from both sides (3x=39). Divide both sides by 3 (x=13). The answer is 13.

You might be interested in

What is the difference between 2,800 and 459?

DENIUS [597]

The difference is 2,341

4 0

3 years ago

I need help with #13

iren2701 [21]

B) m= 1/2
you would use slope formula to find what line passes through those coordinates

7 0

3 years ago

George is considering two different investment options. The first offers 7.4% per year simple interest on the initial deposit. T

pentagon [3]

Answer:

Part A) $\$12,220.00$

Part B) $\$12,134.08$

Part C) The simple interest investment is better than the compounded interest investment at the end of three years.

Part D) see the explanation

Step-by-step explanation:

Part A) Determine the value of the simple-interest investment at the end of three years

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=3\ years\\ P=\$10,000\\r=7.4\%=7.4/100=0.074$

substitute in the formula above

$A=10,000(1+0.074*3)$

$A=10,000(1.222)$

$A=\$12,220.00$

Part B) Determine the value of the compound-interest investment at the end of three years

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=3\ years\\ P=\$10,000\\r=6.5\%=6.5/100=0.065\\n=4$

substitute in the formula above

$A=10,000(1+\frac{0.065}{4})^{4*3}$

$A=10,000(1.01625)^{12}$

$A=\$12,134.08$

Part C) Which investment is better over the first three years?

Compare the two investment

$\$12,134.08 < \$12,220.00$

The compounded interest investment is less than the simple interest investment

therefore

The simple interest investment is better than the compounded interest investment at the end of three years

Part D) How would you advise George to invest his money if he is unsure how long he’ll keep the money in the account?

we have

$A=10,000(1+0.074t)$ ----> simple interest formula as a function of the time t

$A=10,000(1.01625)^{4t}$ ----> compound interest formula as function of the time t

Look to the attached graph below

The red line represents the simple interest investment

The blue curve represents the compounded interest investment

After 0 years and before 4.179 years the red line is over the blue curve, that means the simple interest is better because it gives more money than the compounded interest

After that the blue curve is over the red line that means the compounded quarterly is better because it gives more money than the simple interest

therefore

I advise George to invest his money in the compounded interest investment if he will keep the money for a long time

4 0

3 years ago

How do i solve this?

garri49 [273]

Do it say something like m= a number if so take that number and create a number line and see which one is greater

4 0

4 years ago

5. Write an equation that models exponential decay.

Sliva [168]

Answer:

Step-by-step explanation:

y = ab^x where 0<b<1 for exponential decay

an example would be y = 3(1/7)^x

5 0

3 years ago