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3 years ago

What is the volume of the square pyramid with base edges 32 mm and slant height 34 mm?

Mathematics

1 answer:

NeX [460]3 years ago

5 0

Answer:

The answer to your question is 10240 mm³

Step-by-step explanation:

Data

length of the base = 32 mm

length of the height = 34 mm

Formula

Volume of a pyramid = 1/3 x Area of the base x length of the height

Process

1.- Calculate the area of the base

Area = side x side

= 32 x 32

= 1024 mm²

2.- Find the height of the pyramid using the Pythagorean theorem

height² = 34² - 16²

height² = 1156 - 256

height² = 900

height = 30

3.- Calculate the volume of the pyramid

Volume = 1/3Area x height

= 1/3(1024 x 30)

= (30720)/3 mm³

= 10240 mm³

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Part A) see the explanation

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Step-by-step explanation:

Part A)

we know that

A relationship between two variables, x, and C, represent a proportional variation if it can be expressed in the form $k=\frac{C}{x}$ or $C=kx$

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3 years ago

$1,000, 7% , 2years

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Answer:

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3 years ago

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The factors of the Jared's graph are: (x - 10), (x + 3) and (x + 9)
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(a) The factors

First, we write out the points where the function cross the x-axis.

The points are:

$\mathbf{x = 10}$

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Equate the above points to 0

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$\mathbf{x +9 = 0}$

Hence, the factors are: (x - 10), (x + 3) and (x + 9)

(b) The y-intercept

This is the point where the graph crosses the y-axis.

From the attached graph, the graph crosses the y-axis at -13.5.

Hence, the y-intercept is -13.5

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In (a), we have:

$\mathbf{x -10 = 0}$

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Multiply the above equations

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$\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 }$

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Expand

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Collect like terms

$\mathbf{x^3 + 12x^2 - 10x^2+ 27x - 220x - 270 = 0 }$

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Replace 0 with y

$\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

Hence, the standard form is: $\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

Read more about graphs and functions at:

brainly.com/question/18806107

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