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Semmy [17]
9 months ago
14

On a bike ride, calvin starts at home and goes up a long hill for 30 minutes at just 6 mph. at the top, he turns around and ride

s home along the same path at a speed of 18 mph. what is his average speed for the round-trip?
Mathematics
2 answers:
Masja [62]9 months ago
5 0

9mph is the average speed  for the round-trip.

<h3>What is Average speed?</h3>

The average speed is the total distance traveled by the object in a particular time interval.

Given that Calvin's first leg of the trip took 0.5 hr (30 minutes) at 6 mph.  That means he travelled (0.5hr x 6 mph =) 3 miles.  

He travelled 3 miles on the return trip, by definition (same path home).  

At 18 mph, 3 miles would take (3 miles/18 mph =) 0.1667 hours.  

That makes a total of 6 miles

0.5 + 0.1667= 0.6667 hours.

(6 miles)/(0.6667 hours) = 9 mph

9mph is Calvin's average speed for the round trip.

To learn more on Average speed click:

brainly.com/question/12322912

#SPJ2

omeli [17]9 months ago
3 0

Answer:

<u>9 mph</u>

Step-by-step explanation:

Calvin's first leg of the trip took 0.5 hr (30 minutes) at 6 mph.  That means he travelled (0.5hr x 6 mph =) 3 miles.  He travelled 3 miles on the return trip, by definition (same path home).  At 18 mph, 3 miles would take (3 miles/18 mph =) 0.1667 hours.  That makes a total of 6 miles and (0.5 + 0.1667=) 0.6667 hours.

(6 miles)/(0.6667 hours) = 9 mph is Calvin's average speed for the round trip.

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Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt
tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

f(x)= \sqrt{\dfrac{x+1}{x-1}}

g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

\dfrac{x+1}{x-1}>0

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

x+1\leq 0\Rightarrow x\leq -1

x-1\leq 0\Rightarrow x\leq 1

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0
3 years ago
Cassandra assigns values to some of the measures of triangle ABC. If angle A measures 30°, a = 6, and b = 18, which is true?
Anna [14]

Answer:

The triangle does not exist because sin(A)/a can not be equal to sin(B)/b

Step-by-step explanation:

we know that

step 1

Find the measure of angle B

Applying the law of sines

\frac{sin(A)}{a}=\frac{sin(B)}{b}

we have

A=30\°

sin(30\°)=1/2

a=6\ units

b=18\ units

substitute

\frac{(1/2)}{6}=\frac{sin(B)}{18}

\frac{1}{12}=\frac{sin(B)}{18}

sin(B)=\frac{18}{12}

sin(B)=\frac{3}{2}=1.5

Remember that the value of sine can not be greater than 1

therefore

The triangle does not exist because sin(A)/a can not be equal to sin(B)/b

8 0
3 years ago
Is -2(-3) a positive or negative answer???
Natalija [7]

Answer: positive

Step-by-step explanation: it’s positive because if you multiply two negative numbers they cancel each other out and it makes a positive number

5 0
3 years ago
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Schach [20]

Answer:

x = -\frac{19}{60}

Step-by-step explanation:

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i think this is

3 0
3 years ago
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