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vladimir2022 [97]

3 years ago

11

13. Mr. Ralph took out a 10-year term policy with a face value off dollars. Over the lifetime of the policy, he pays monthly pay

ments of m dollars. He dies after 12 years. How much will his family receive
from the insurance company?

1 answer:

Sliva [168]3 years ago

6 0

Answer:

0

Step-by-step explanation:

There will be no death benefit. The policy expired after 10 years.

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The current population of the Earth is estimated to be about 7,440,000,000 people. Express this number using scientific notation

SCORPION-xisa [38]

Answer:

7.44 × 10⁹

Step-by-step explanation:

You would take a decimal point from the last zero to in-between 7 and 4 and see how many places you moved it then write the scientific formula.

9 spaces so it would be 7.44 × 10⁹

8 0

2 years ago

Round 436486.48649 nearest whole number?

Annette [7]

Its 436486 because you don't need to round it up

7 0

3 years ago

PLZZ HELP ME 20 POINTS AND BRAINLIEST!

omeli [17]

Answer:

The price of price of the stock after it has been owned for 12 weeks is $92.55

Step-by-step explanation:

Given: The price of a particular stock is represented by the linear equation

y = -0.91x + 103.47

where x represents the number of weeks the stock has been owned and y represents the price of the stock, in dollars.

We have to find the price of price of the stock after it has been owned for 12 weeks.

Since , x represents the number of weeks the stock has been owned.

Thus, by substitute, x = 12

We get the value of y , the price of stocks.

Thus, y(x) = -0.91x + 103.47

⇒ y(12) = -0.91(12) + 103.47

⇒ y(12) = -10.92 + 103.47

Solving , we get,

⇒ y(12) = 92.55

Thus, the price of price of the stock after it has been owned for 12 weeks is $92.55.

8 0

2 years ago

Read 2 more answers

32% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a

Tems11 [23]

Answer:

a) $P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

b) $P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668$

c) $P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816$

Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=10, p=0.32)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

Part b

$P(X> 2)=1-P(X\leq 2)=1-[P(X=0)+P(X=1)+P(X=2)]$

$P(X=0)=(10C0)(0.32)^0 (1-0.32)^{10-0}=0.0211$

$P(X=1)=(10C1)(0.32)^1 (1-0.32)^{10-1}=0.0995$

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

$P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668$

Part c

$P(2 \leq x \leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)$

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

$P(X=3)=(10C3)(0.32)^3 (1-0.32)^{10-3}=0.264$

$P(X=4)=(10C4)(0.32)^4 (1-0.32)^{10-4}=0.218$

$P(X=5)=(10C5)(0.32)^5 (1-0.32)^{10-5}=0.123$

$P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816$

6 0

3 years ago

3. Three years ago, Jane was three times as old as Alice. In two years time, the sum of their ages will be 62. Determine their p

anzhelika [568]

3 yrs ago:

Alice - x
Jane - 3x

Fast forward 2 years... 1 year ago:

Sum of their ages = 62

Equation to solve: x + 3x = 62
4x = 62
----- -----
4 4

x = 15.5

From this, we can deterime that Alice is 15 1/2 years old.

Then, plug in 15.5 for x in 3x to find Jane's age.

15.5 × 3 = 46.5

From this, we can determine that Jane is 46 1/2 years old.

I hope this helps you to understand this problem better.

5 0

3 years ago

Read 2 more answers