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Nataly_w [17]
1 year ago
6

Divide. Assume that all variables in the denominator are nonzero.

Mathematics
2 answers:
Genrish500 [490]1 year ago
6 0

Answer:

4a^{5}

Step-by-step explanation:

\frac{64}{16} = 4

When the bases are the same and you are dividing you subtract the exponents.  It is easier to see why when you write the problem out in expanded form.

\frac{aaaaaabbbbbbb}{abbbbbbb}  If you cross out all of the a's on top with the a's on the bottom, you are left with only 1 a (6-1 = 5)  If you do not see an exponent, it is understood to be 1.  All of the b's on the top and bottom cross out. (7-7 = 0)  Anything to the zero power = 1.

yarga [219]1 year ago
4 0

Answer:

4a^{5}

Step-by-step explanation:

The easiest way to start this solving is simplifying the numbers:

start by dividing 64 by 16. This gets you 4.

Then simplify the variables. Let's start with <em>a</em>:

to do this, we will start by moving all the <em>a'</em>s to the same line so we can multiply them

multiplying like variables means that you are actually just adding their exponents

when moving a variable up or down on the fraction, the exponent will flip signs (positive to negative, or negative to positive)

in this case, we have a^{6} in the numerator and a^{1}, so it would be easiest to move   a^{1} above so that it the equation will become \frac{4a^{6}a^{-1}b^{7}   }{b^{7} }

now we can subtract 1 from 6 and get  \frac{4a^{5}b^{7}   }{b^{7} }

Now let's work on simplifying <em>b:</em>

both the numerator and denominator have b^{7} in it

so if we move the <em>b</em> denominator up, the numerator ends up as     {4a^{5}b^{7}b^{-7} }

which makes both <em>b'</em>s cancel out, making your final answer 4a^{5}

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</span>

I hope my answer has come to your help. Have a nice day ahead and may God bless you always!
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