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Rashid [163]
2 years ago
6

A quadratic equation has exactly one real number solution.Which is the value of its discriminant ?-1,0,1 or 2

Mathematics
1 answer:
Ivanshal [37]2 years ago
4 0

Answer:

The value of the discriminant is 0

Step-by-step explanation:

The discriminant of a quadratic equation is calculated as thus:

b² - 4ac and it is represented by letter D.

Hence, D = b² - 4ac..

This discriminant can take either of 3 range of values.

1. D > 0. This implies that the discriminant has a value greater than 0 and this means that the root has 2 different real solutions

2. D = 0. This implies that the discriminant equals 0 and this means that the root has only 1 solution.

3. D < 0. This implies that the discriminant is less than 0 and this means that the root has 2 different complex solutions.

Hence, D = 0 is the correct answer to this question.

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To have batting aberages over .500, how may hits in 45 times at bat would raul and karen need.
Oduvanchick [21]

i believe it's 22.5 out of 45 to get exactly .500

4 0
3 years ago
Find the sum
lakkis [162]

Answer:

Numerator = 2(b^2+a^2)    or equivalently 2b^2+2a^2

Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3

Step-by-step explanation:

Let

S = 2b/(b+a)^2 + 2a/(b^2-a^2)   factor denominator

= 2b/(b+a)^2 + 2a/((b+a)(b-a))     factor denominators

= 1/(b+a) ( 2b/(b+a) + 2a/(b-a))    find common denominator

= 1/(b+a) ((2b*(b-a) + 2a*(b+a))/((b+a)(b-a))   expand

= 1/(b+a)(2b^2-2ab+2ab+2a^2)/((b+a)(b-a))  simplify & factor

= 2/(b+a)(b^2+a^2)/((b+a)(b-a))  simplify & rearrange

= 2(b^2+a^2)/((b+a)^2(b-a))

Numerator = 2(b^2+a^2)    or equivalently 2b^2+2a^2

Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3

4 0
2 years ago
G(x) = 6 - 2x<br> Find g(-4).
sergeinik [125]

Answer:

\huge \boxed{g( - 4) = 14}

Step-by-step explanation:

g(x) = 6 - 2x

To find g(-4) , substitute the value of x that's - 4 into g(x). That is for every x in g(x) , replace it with - 4

We have

g( - 4) = 6 - 2( - 4) \\  = 6 + 8 \\  = 14  \:  \:  \:  \:  \:

We have the final answer as

<h3>g(-4) = 14</h3>

Hope this helps you

5 0
2 years ago
A bike and skate shop rents bike for $21 per day and pairs of skates for $20 per day. To remain viable, the shop needs to make a
Leya [2.2K]
Let the number of bike be x and the number of skates be y, then
21x + 20y ≥ 362 . . . (1)
2y = x . . . (2)

Putting (2) into (1), then
21(2y) + 20y ≥ 362
42y + 20y ≥ 362
62y ≥ 362
y ≥ 5.84

The least number of pairs of skates they need to rent each day to make their minimum is 6.
7 0
3 years ago
What is the solution to this equation? 2x+2=10
mrs_skeptik [129]
X=4 ........................................
8 0
2 years ago
Read 2 more answers
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