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Y_Kistochka [10]
2 years ago
7

How to make 3 dimensional object become 4 dimensional object

Mathematics
1 answer:
NISA [10]2 years ago
6 0

Using Hinton's method;

  • Draw two ordinary 3D cubes in 2D space, one encompassing the other, separated by an "unseen" distance
  • Then draw lines between their equivalent vertices.
  • The eight lines connecting the vertices of the two cubes in this case represent a single direction in the "unseen" fourth dimension.

<h3>What is a 4 dimensional shape?</h3>

A four-dimensional shape (4D) is a mathematical extension of a three-dimensional or 3D space.

Three-dimensional space is the simplest possible abstraction of the observation that one only needs three numbers, called dimensions, to describe the sizes or locations of objects.

Using Hinton's method;

  • Draw two ordinary 3D cubes in 2D space, one encompassing the other, separated by an "unseen" distance
  • Then draw lines between their equivalent vertices.
  • The eight lines connecting the vertices of the two cubes in this case represent a single direction in the "unseen" fourth dimension.

Learn more about dimensional shapes here:

brainly.com/question/12280037

#SPJ1

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The lower base of the frustum shown is a square 8 ft on each side. The upper base is a square 4 ft on each side. If the altitude
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7 0
4 years ago
2e - 3f = 4
Varvara68 [4.7K]

Answer:

The value of e is -1 and f is -2.

Step-by-step explanation:

The steps are :

2e - 3f = 4 -  -  - (1)

2e - 5f = 8 -  -  - (2)

2e - 3f - 2e - ( - 5f) = 4 - 8

2f =  - 4

f =  - 4 \div 2

f =  - 2

substitute \: f =  - 2  \: into \: (1)

2e - 3( - 2) = 4

2e + 6 =   4

2e = 4 - 6

2e =  - 2

e =  - 2 \div 2

e =  - 1

6 0
3 years ago
Read 2 more answers
Prove that if an integer is a perfect square and a perfect cube, simultaneously, then it is either of the form 7k or 7k+1
Bogdan [553]
If an integer is both a square and a cube, it can be of the form:
<span>(<span>a3</span><span>)^2</span></span>
Now,
since a cube can be of the form 7k or 7k+-1(thanks to FoolForMath),
 we write
<span><span>a^3</span>=7k</span>
and get the no to be
49k^2
, which is in the form of 7 times something
<span>49<span>k^2</span>=7×(7<span>k^2</span>)</span>
Now put
<span><span>a^3</span>=7k+−1</span> Square it
and you'll get a number in the form of (7times something +1)
5 0
3 years ago
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