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2 years ago

How to make 3 dimensional object become 4 dimensional object

Mathematics

1 answer:

NISA [10]2 years ago

6 0

Using Hinton's method;

Draw two ordinary 3D cubes in 2D space, one encompassing the other, separated by an "unseen" distance
Then draw lines between their equivalent vertices.
The eight lines connecting the vertices of the two cubes in this case represent a single direction in the "unseen" fourth dimension.

<h3>What is a 4 dimensional shape?</h3>

A four-dimensional shape (4D) is a mathematical extension of a three-dimensional or 3D space.

Three-dimensional space is the simplest possible abstraction of the observation that one only needs three numbers, called dimensions, to describe the sizes or locations of objects.

Using Hinton's method;

Draw two ordinary 3D cubes in 2D space, one encompassing the other, separated by an "unseen" distance
Then draw lines between their equivalent vertices.
The eight lines connecting the vertices of the two cubes in this case represent a single direction in the "unseen" fourth dimension.

Learn more about dimensional shapes here:

brainly.com/question/12280037

#SPJ1

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A cone-shaped pile of sawdust has a base diameter of 38 feet, and is 14 feet tall. Find the volume of the pile

Romashka-Z-Leto [24]

Answer:

Given: Diameter of cone = 38 feet and height of cone = 14 feet.

Volume of cone V with radius r is one-third the area of the base B times the height h.

i,e $V = \frac{1}{3} B \cdot h$ = $\frac{1}{3} \pi r^2h$ ......[1]

,where B = $\pi r^2$

First find the radius(r);

Using Diameter(D) = 2r

38 =2r

Divide both side by 2 we get;

$\frac{38}{2} =\frac{2r}{2}$

Simplify:

19 = r

or r =19 feet

Now, substitute the value of r = 19 feet and h = 14 feet in [1] [ Use value of $\pi = \frac{22}{7}$ ]

then, we have:

$V = \frac{1}{3} \pi r^2h = \frac{1}{3} \cdot \frac{22}{7} \cdot (19)^2 \cdot (14)$

V = $=\frac{1}{3}\cdot 22 \cdot 19 \cdot 19 \cdot 2 = \frac{22 \cdot 19 \cdot 19 \cdot 2}{3}$

V = $\frac{15884}{3} =5,294.66667$ ≈ 5,294.67 cubic feet.

therefore, the volume of pile is; ≈ 5,294.67 cubic feet.

4 0

3 years ago

Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m

GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

$d=\sqrt{\frac{3h}{2} }$

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

$d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)$

For Addison h=85(1/3)

$d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)$

Subtracting both distances we get

$8\sqrt{2}-6\sqrt{2} =2\sqrt{2}$

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0

3 years ago

What are the missing parts that correctly complete the proof

bonufazy [111]

Answer:

2. $\overline{AX}\cong \overline{BX}$

3. $PX \perp AB$ - definition of perpendicular

4. $\angle PXA \cong \angle PXB$ - all right angles are congruent

6. $\triangle AXP\cong \triangle BXP$

7. $\overline{PA} \cong \overline{PB}$

Step-by-step explanation:

<u>Given: </u>Point P is the perpendicular bisector of AB

<u>Prove: </u>P is equidistant from the endpoints AB

<u>Proof.</u>

1. Point P is on the perpendicular bisector of AB - given

2. $\overline{AX}\cong \overline{BX}$ - definition of bisector

3. $PX \perp AB$ - definition of perpendicular

4. $\angle PXA \cong \angle PXB$ - all right angles are congruent

5. $\overline{PX} \cong \overline{PX}$ - reflexive property of congruence

6. $\triangle AXP\cong \triangle BXP$ - SAS congruency postulate

7. $\overline{PA} \cong \overline{PB}$ - corresponding parts of congruent triangles are congruent

8. Point P is equidistant from the endpoints of AB - definition of equidistant

5 0

3 years ago

What is the value of y?<br> 03<br> 04<br> 05<br> 06

alexandr1967 [171]

Answer:

Step-by-step explanation:

Subtract 4, divide by 2, then get 3

7 0

3 years ago

If (5-3i)(x+iy)/(4-5i) = (2+i)^2-(3-4i)^2, then x=___ and y=____

Leona [35]

This looks complicated

lets simplify both sides

By multiplying top and bottom by the conjugate:-

left side = (5-3i)(x + iy) (4+5i) (5-3i)(x + iy) (4+5i)
------------------------ = ------------------------
(4-5i)(4+5i) 41

right side = (2 + i + 3-4)(2+i - 3 + 4i) (by Difference of 2 squares)

= 5-3i)(-1 + 4i)

so as left side = right side

(5-3i)(x+yi)(4+5i) = 41 (5-3i)(-1+5i)

5-3i is common so:-

(x + iy)(4+5i) = 41(-1+5i)

4x +5xi + 4yi - 5y = -41 + 205i

4x - 5y + (5x + 4y)i = -41 + 205i

EQuating coefficients we are left with the system of equations

4x - 5y = -41
5x + 4y = 205

solving this gives x = 21 and y = 25

8 0

3 years ago