Step-by-step explanation:
true equation when x is replaced by 2, and is a false ... is written in terms of P, R, and T.” In some cases, before using a formula it may be ... (2) a number line graph, or (3) interval notation.
Answer:
The answer is all of them.
Step-by-step explanation:
All of them can make a line of symmetry for the letter I
Hope this helps
Answer:
Right Triangles and the Pythagorean Theorem
1.The Pythagorean Theorem, a2+b2=c2, a 2 + b 2 = c 2 , can be used to find the length of any side of a right triangle.
2.The side opposite the right angle is called the hypotenuse (side c in the figure).
Answer:
40320
Step-by-step explanation:
There are 8 different people we could assign to the first task. Now there are 7 tasks and 7 people left. There are 7 different people we could assign to the next task. And so on
8 *7*6*5*4*3*2*1
8!
40320
Hi there what you need is lagrange multipliers for constrained minimisation. It works like this,
V(X)=α2σ2X¯1+β2\sigma2X¯2
Now we want to minimise this subject to α+β=1 or α−β−1=0.
We proceed by writing a function of alpha and beta (the paramters you want to change to minimse the variance of X, but we also introduce another parameter that multiplies the sum to zero constraint. Thus we want to minimise
f(α,β,λ)=α2σ2X¯1+β2σ2X¯2+λ(\alpha−β−1).
We partially differentiate this function w.r.t each parameter and set each partial derivative equal to zero. This gives;
∂f∂α=2ασ2X¯1+λ=0
∂f∂β=2βσ2X¯2+λ=0
∂f∂λ=α+β−1=0
Setting the first two partial derivatives equal we get
α=βσ2X¯2σ2X¯1
Substituting 1−α into this expression for beta and re-arranging for alpha gives the result for alpha. Repeating the same steps but isolating beta gives the beta result.
Lagrange multipliers and constrained minimisation crop up often in stats problems. I hope this helps!And gosh that was a lot to type!xd
