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zysi [14]
3 years ago
12

Find the point-slope form through: (4, 3), parallel to y =7/6x + 1

Mathematics
1 answer:
pickupchik [31]3 years ago
6 0

Answer: (y - 3) = 7/6 (x - 4)

Step-by-step explanation:

The formula for point slope form is (y-y₁) = m(x-x₁)

Parallel lines will always have the same slope, so the slope of the new line is still 7/6.

The line goes through point (4, 3),

so x₁ = 4, and y₁ = 3 as points are written as (x, y).

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Step-by-step explanation:

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2 years ago
Which equation represents the line that is perpendicular to and passes through (-12,6)?.
Evgesh-ka [11]

The equation that represents the line that is perpendicular is

3y + 5x = -42

The standard equation of a line in point-slope form is expressed as:

y-y_1=m(x-x_1)

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  • (x1, y1) is any point on the line.

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Substitute the point (-12, 6) and the slope m = -5/3 into the equation above to have:

y-6=-5/3(x-(-12))\\3(y-6)=-5(x+12)\\3y-18=-5x-60\\3y = -5x - 60 + 18\\3y + 5x = -42\\

Hence the equation that represents the line that is perpendicular is

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Learn more on equation of a line here:brainly.com/question/19417700

7 0
2 years ago
Coefficient x^2 in the expansion of (2+x)^5
Monica [59]
Alright, expand the given equation:
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I can't do the actually expansion for you, it would take a decently long time. You should be able to, its a good practice. Good luck!
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Step-by-step explanation:

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