3 years ago

Find the point-slope form through: (4, 3), parallel to y =7/6x + 1

Mathematics

1 answer:

pickupchik [31]3 years ago

6 0

Answer: (y - 3) = 7/6 (x - 4)

Step-by-step explanation:

The formula for point slope form is (y-y₁) = m(x-x₁)

Parallel lines will always have the same slope, so the slope of the new line is still 7/6.

The line goes through point (4, 3),

so x₁ = 4, and y₁ = 3 as points are written as (x, y).

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Consider the following function. f(x) = 9 − x2/3 Find f(−27) and f(27). f(−27) = f(27) = Find all values c in (−27, 27) such tha

oksano4ka [1.4K]

I guess the function is $f(x)=9-x^{2/3}$ . Then $f(-27)=0$ and $f(27)=0$ .

The derivative is $f'(x)=-\dfrac23 x^{-1/3}$ , but there is no $c$ such that

$-\dfrac23c^{-1/3}=0$

This doesn't contradict Rolle's theorem because $f'(0)$ does not exists. In other words, $f$ is not differentiable on (-27, 27), so the conditions of Rolle's theorem are not met. (Looks like that would be the last option, or the second to last option if the last one is "Nothing can be concluded")