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Mumz [18]
3 years ago
11

What is the quotient of StartFraction 7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline EndFraction? Star

tFraction 1 Over 343 EndFraction One-seventh 7 49.
Mathematics
1 answer:
Komok [63]3 years ago
7 0

The quotient of the number given number  7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline is 7.

<h3>What is the quotient?</h3>

Quotient is the resultant number which is obtain by dividing a number with another. Let a number a is divided by number b. Then the quotient of these two number will be,

q=\dfrac{a}{b}

Here, (<em>a, b</em>) are the real numbers.

The number StartFraction 7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline EndFraction, given can be written as,

\dfrac{7^{-1}}{7^{-2}}

Let the quotient of this division is n. Therefore,

n=\dfrac{7^{-1}}{7^{-2}}

A number in numerator of a fraction with negative exponent can be written in the denominator with the same but positive exponent and vise versa. Therefore,

n=\dfrac{7^{2}}{7^{1}}\\n=7

Hence, the quotient of the number given number  7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline is 7.

Learn more about the quotient here;

brainly.com/question/673545

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The rate of change aka slope is -2
6 0
3 years ago
Find the absolute maximum and minimum values of the function below. f(x) = x3 − 9x2 + 3, − 3 2 ≤ x ≤ 12 Solution Since f is cont
Neko [114]

Answer:

There are an absolute minimum (x = 6) and an absolute maximum (x = 12).

Step-by-step explanation:

The correct statement is described below:

Find the absolute maximum and minimum values of the function below:

f(x) = x^{3}-9\cdot x^{2}+ 3, 2 \leq x \leq 12

Given that function is a polynomial, then we have the guarantee that function is continuous and differentiable and we can use First and Second Derivative Tests.

First, we obtain the first derivative of the function and equalize it to zero:

f'(x) = 3\cdot x^{2}-18\cdot x

3\cdot x^{2}-18\cdot x = 0

3\cdot x \cdot (x-6) = 0 (Eq. 1)

As we can see, only a solution is a valid critical value. That is: x = 6

Second, we determine the second derivative formula and evaluate it at the only critical point:

f''(x) = 6\cdot x -18 (Eq. 2)

x = 6

f''(6) = 6\cdot (6)-18

f''(6) =18 (Absolute minimum)

Third, we evaluate the function at each extreme of the given interval and the critical point as well:

x = 2

f(2) = 2^{3}-9\cdot (2)^{2}+3

f(2) = -25

x = 6

f(6) = 6^{3}-9\cdot (6)^{2}+3

f(6) = -105

x = 12

f(12) = 12^{3}-9\cdot (12)^{2}+3

f(12) = 435

There are an absolute minimum (x = 6) and an absolute maximum (x = 12).

6 0
3 years ago
Which equation represents the situation
IrinaK [193]

....................................

7 0
3 years ago
2/5(g - 7) = 3 <br> can i please get some help..
Flura [38]

Answer:

14.500

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (2)/(5)*(g-7)-(3)=0

Step by step solution :

STEP

1

:

           2

Simplify   —

           5

Equation at the end of step

1

:

  2              

 (— • (g - 7)) -  3  = 0

  5              

STEP

2

:

Equation at the end of step 2

 2 • (g - 7)    

 ——————————— -  3  = 0

      5        

STEP

3

:

Rewriting the whole as an Equivalent Fraction

3.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  5  as the denominator :

        3     3 • 5

   3 =  —  =  —————

        1       5  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

2 • (g-7) - (3 • 5)     2g - 29

———————————————————  =  ———————

         5                 5  

Equation at the end of step

3

:

 2g - 29

 ———————  = 0

    5  

STEP

4

:

When a fraction equals zero

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 2g-29

 ————— • 5 = 0 • 5

   5  

Now, on the left hand side, the  5  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  2g-29  = 0

Solving a Single Variable Equation:

4.2      Solve  :    2g-29 = 0

Add  29  to both sides of the equation :

                     2g = 29

Divide both sides of the equation by 2:

                    g = 29/2 = 14.500

One solution was found :

g = 29/2 = 14.500

8 0
3 years ago
Read 2 more answers
A book is 6 inches wide and 9 inches tall. A publisher wants to use a scale factor of 1.5 to enlarge a book. What will the area
MissTica
6 inches enlarged by 1.5 = 9 inches
9 inches enlarged by 1.5 = 13.5 inches

area = 9 × 13.5
= 121.5 square inches
3 0
3 years ago
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