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Mumz [18]
3 years ago
11

What is the quotient of StartFraction 7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline EndFraction? Star

tFraction 1 Over 343 EndFraction One-seventh 7 49.
Mathematics
1 answer:
Komok [63]3 years ago
7 0

The quotient of the number given number  7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline is 7.

<h3>What is the quotient?</h3>

Quotient is the resultant number which is obtain by dividing a number with another. Let a number a is divided by number b. Then the quotient of these two number will be,

q=\dfrac{a}{b}

Here, (<em>a, b</em>) are the real numbers.

The number StartFraction 7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline EndFraction, given can be written as,

\dfrac{7^{-1}}{7^{-2}}

Let the quotient of this division is n. Therefore,

n=\dfrac{7^{-1}}{7^{-2}}

A number in numerator of a fraction with negative exponent can be written in the denominator with the same but positive exponent and vise versa. Therefore,

n=\dfrac{7^{2}}{7^{1}}\\n=7

Hence, the quotient of the number given number  7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline is 7.

Learn more about the quotient here;

brainly.com/question/673545

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Given the right triangle shown below.if Cos A =15/17 and tan A=8/15 which of the following represents the length of BC
otez555 [7]

Answer:

The Figure for Right triangle is below,

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Step-by-step explanation:

Given:

Consider a right triangle ABC, Such that

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To Find:

BC = ?

Solution:

In Right Angle Triangle ABC, Cosine and Tangent identity

\cos A = \dfrac{\textrm{side adjacent to angle C}}{Hypotenuse}\\

\tan A= \dfrac{\textrm{side opposite to angle A}}{\textrm{side adjacent to angle A}}

BUT,

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On Comparing,

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Also Pythagoras theorem is Satisfies,

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The Figure for Right triangle is below,

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