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1 year ago

Interpreting graphs of functions

Mathematics

2 answers:

Elena L [17]1 year ago

4 0

Answer:

non-linear
40
1/2

Step-by-step explanation:

This is a non-linear function specifically it is an oscillating function
The initial position of the weight occurs at t=0 and from the graph we see that at t=0, the weight position is 40 centimeters
The weight is said to reach equilibrium when its position is at 0 cm. From the graph we can see that the function first reaches 0 cm at t=0.5 seconds or at t= 1/2 second

horsena [70]1 year ago

3 0

Answer: non-linear 40 1/2 Step-by-step explanation: This is a non-linear function specifically it is an oscillating function The initial position of the weight occurs at t=0 and from the graph we see that at t=0, the weight position is 40 centimeters The weight is said to reach equilibrium when its position is at 0 cm. From the graph we can see that the function first reaches 0 cm at t=0.5 seconds or at t= 1/2 second

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Solve the system of equations. x+y=4 y=x^2 - 8x + 16 a) {(-3,7).(-4, 8)} b) [(4,0)} c) {(3,1),(4,0) d) {(3,7). (4.0)} e) none

Marysya12 [62]

Answer: The required solution of the given system is

(x, y) = (3, 1) and (4, 0).

Step-by-step explanation: We are given to solve the following system of equations :

$x+y=4~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\y=x^2-8x+16~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

From equation (i), we have

$x+y=4\\\\\Rightarrow y=4-x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

Substituting the value of y from equation (iii) in equation (ii), we get

$y=x^2-8x+16\\\\\Rightarrow 4-x=x^2-8x+16\\\\\Rightarrow x^2-8x+16-4+x=0\\\\\Rightarrow x^2-7x+12=0\\\\\Rightarrow x^2-4x-3x+12=0\\\\\Rightarrow x(x-4)-3(x-4)=0\\\\\Rightarrow (x-3)(x-4)=0\\\\\Rightarrow x-3=0,~~~~~~~x-4=0\\\\\Rightarrow x=3,~4.$

When, x = 3, then from (iii), we get

$y=4-3=1.$

And, when x = 4, then from (iii), we get

$y=4-4=0.$

Thus, the required solution of the given system is

(x, y) = (3, 1) and (4, 0).

8 0

3 years ago

Math help @LIEMONDER

klio [65]

First picture)
I: 5x+2y=-4
II: -3x+2y=12

add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2

insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3

(-2,3)

question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs

insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults

insert adults into II:
33-8=childs
25=childs

so it's the last option

question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6

so it's the last option

question 8)
I: x+y=12
II: x-y=6

subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3

insert y into I:
x+3=12
x=9

(9,3)

question 9)
I: x+y=6
II: x=y+5

if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6

which is the second option :)

5 0

3 years ago

23 and 24 I need help please

Gnoma [55]

Answer:

They should purchase the snack with the purple box. This is the answer for 23, i don't know what 24 is sorry.

Step-by-step explanation:

24÷3=8

8×5=40

so the first snacks would cost them $40.

then:

24÷4=6

6×6=36

so the second snacks would cost them $36

5 0

3 years ago

If the beginning temperature was -13 at 5:00 a.m

Neporo4naja [7]

Answer:

what the question in this

Step-by-step explanation:

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3 years ago

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stealth61 [152]

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3 years ago

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