Answer:
The coordinates I chose are (0,-5) and (2,-4)
Step-by-step explanation:
9514 1404 393
Answer:
7 times
Step-by-step explanation:
Each meal weighs (24 oz)/(16 oz/lb) = 1.5 lb. The number of meals to be delivered each day is ...
(34.5 lb/day)/(1.5 lb/meal) = 23 meals/day
If we assume that meals can remain in the car from one day to the next, we only need to compute the total number of loads in 4 days.
(23 meal/day)(4 days)/(15 meals/load) = 6 2/15 loads/4-days
That is loading the car 6 times is not enough. They need to load the car 7 times in 4 days.
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If we assume that meals cannot remain in the car from one day to the next, then the car must be loaded 2 times per day. That's 8 times in 4 days.
The answer depends on your assumptions about loading the car.
Answer:
A = ≈4.17 ft²
Step-by-step explanation:
Even though the problem deals with shapes and area, we can use algebra to solve for the missing area of Square C. Gven the following formulas:
A (square) = s², where s = the measure of one side
A (rectangle) = l x w, where l = length and w = width
We can set up equations to solve for the side length of Square C to find the area. Since the area of Square A = 6 ft²:
A = 6 or 6 = s² so √6 = √s² or s = √6
So, the length of Rectangle B is √6 and the area = 5 ft², so we can solve for 'w', which is also the side length of Square C:
A = 5 ft² or 5 = l x w so 5 = √6w and w = 5/√6
Lastly, find the area of Square C:
A = s² or A = (5/√6)(5/√6) or area = ≈4.17 ft²
BAF and FAD I took the test !