A fair coin is flipped seven times. what is the probability of the coin landing tails up at least two times?

Mathematics

1 answer:

GaryK [48]1 year ago

7 0

The required probability of the coin landing tails up at least two times is 15/16.

Given that,
A fair coin is flipped seven times. what is the probability of the coin landing tails up at least two times is to be determined.

<h3>What is probability?</h3>

Probability can be defined as the ratio of favorable outcomes to the total number of events.

Here,
In the given question,
let's approach inverse operation,
The probability of all tails = 1 / 2^7 because there is only one way to flip these coins and get no heads.
The probability of getting 1 head = 7 /2^7
Adding both the probability = 8 / 2^7
Probability of the coin landing tails up at least two times = 1 - 8/2^7
= 1 - 8 / 128
= 120 / 128
= 15 / 16

Thus, the required probability of the coin landing tails up at least two times is 15/16.

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What is a simple definition of time?

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Write the point slope form of the equation of the line using the point (-4,-2)

Gre4nikov [31]

Answer:

$y + 2 = \frac{5}{4} (x + 4)$

Step-by-step explanation:

1) First, find the slope of the line. Take two points the line intersects and use them for the slope formula, $\frac{y_2-y_1}{x_2-x_1}$ . We already know the line intersects (-4, -2). Just choose any one of the points you can see the line intersecting (in this case, I chose (0,3)) and plug in its values, too. Then solve:

$\frac{(3)-(-2)}{(0)-(-4)} \\\frac{3+2}{0+4} \\\frac{5}{4}$

So, the slope is $\frac{5}{4}$ .

2) Now that you have the slope, plug in values for the point-slope formula, $y - y_1 = m (x - x_1)$ . In order to write a linear equation with it, the $x_1$ , $y_1$ , and $m$ have to be substituted for with real values. The $m$ represents the slope - which means that we should place $\frac{5}{4}$ there. The $x_1$ and $y_1$ represent the x and y values of a point - and the questions wants us to use (-4, -2), so substitute -4 for $x_1$ and -2 for $y_1$ :