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Nady [450]
3 years ago
12

The answers and how to solve them

Mathematics
1 answer:
Gwar [14]3 years ago
7 0
A.30x+1 that's all I got
You might be interested in
3(2x+8)=8x+46 answer
MrMuchimi
3(2x+8)=8x+46
6x+24=8x+46
-2x+24=46
-2x=22
x=-11

3(2(-11)+8)=8(-11)+46
3(-22+8)=-88+46
3(-14)=-42
-42=-42

Hope I didn't mess up for your sake
4 0
3 years ago
By what percentages are Sweden's high category and medium category less than the United States' categories (to the nearest perce
Korolek [52]

REQUIRED CHART :

The required chart has been attached

Answer:

31.8%

30.0%

Step-by-step explanation:

Required :

To obtain the Difference between Sweden and United States high and medium categories to the nearest %

Sweden :

High category = $23.51

Medium category = $15.73

United States :

High category = $34.48

Medium category = $22.46

Percentage Difference :

High category : (34.48 - 23.51) / 34.48 * 100% = 31.8%

Medium category : (22.46 - 15.73) / 22.46 * 100% = 29.96% = 30.0%

7 0
3 years ago
Use the remainder theorem to determine if x=6 is a zero of the following polynomial, and find the quotient and the remainder.
Svet_ta [14]
I think your answer is C correct me if I’m wrong
5 0
2 years ago
in a random sample of 200 people, 154 said that they watched educational television. fine the 90% confidence interval of the tru
melisa1 [442]

Answer:

[0.7210,0.8189] = [72.10%, 81.89%]

Step-by-step explanation:

The sample size is  

n = 200

the proportion is

p = 154/200 = 0.77

<em>Since both np ≥ 10 and n(1-p) ≥ 10 </em>

<em>We can approximate this discrete binomial distribution with the continuous Normal distribution. As the sample size is large enough, not applying the continuity correction factor makes no significant  difference. </em>

The approximation would be to a Normal curve with this parameters:

<em>Mean </em>

p = 0.77

<em>Standard deviation </em>

\bf s=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.77*0.23}{200}}=0.0298

The 90% confidence interval for the proportion would be then  

\bf  [0.77-z^*0.0298, 0.77+z^*0.0298]

where \bf z^* is the 10% critical value for the Normal N(0,1) distribution , this is a value such that the area under the N(0,1) curve outside the interval \bf [-z^*,z^*] is 10%=0.1

We can either use a table, a calculator or a spreadsheet to get this value.

In Excel or OpenOffice Calc we use the function

<em>NORMSINV(0.95) and we get a value of 1.645 </em>

The 90% confidence interval for the proportion is then

\bf  [0.77-1.645^*0.0298, 0.77+1.645^*0.0298]=[0.7210,0.8189]

This means there is a 90% probability that the proportion of people who watch educational television is between 72.10% and 81.89%

If the television company wanted to publicize the proportion of viewers, do you think it should use the 90% confidence interval?

Yes, I do.

5 0
3 years ago
36 miles per hour what is this rate in feet per second
Georgia [21]
I believe it would be 52.8 fps.
8 0
3 years ago
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