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2 years ago

9

I need help ASAP please

1 answer:

RSB [31]2 years ago

4 0

Answer:

5:10

6 (-2,0)

7 (-5,6)

8 (5,3)

9 No, ab=8 CD=6

Step-by-step explanation:

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Which expression’s product is modeled by the tiles? A. (x + 1)(x + 3) B. x(x + 3) C. 3(x + 1) D. (3x + 1)(x + 1)

timurjin [86]

Answer:

C

Step-by-step explanation:

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2 years ago

Marcus has $40 in his pocket. Joseph has twice as much as Marcus; Jenna has half as much as Marcus, and Sam has 1/3 as much as M

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3 years ago

Read 2 more answers

Solve X²-5X-14=0 using quadratic formula

il63 [147K]

Answer:

x=-2 or x=7

Step-by-step explanation:

X²-5X-14=0 find the factors of -14x² which is -7x and +2x

X² -7x + 2x - 14 = 0 factorize

x(x-7) + 2(x-7) = 0

(x+2)(x-7) =0

x+2 = 0 or x-7= 0

x=-2 or x=7

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3 years ago

Find an equation of a line tagent to the circle x^2+(y-3)^2=34 at the point (5,0)

tigry1 [53]

Answer:

First, plot your circle. the Center is (0, 3) and the radius is $\sqrt{34}$

Now to find your slope move from the (0, 3) to (5, 0)

$\frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{0 - 3}{5 - 0} = -\frac{3}{5}$

The slope of a perpendicular line is opposite and reciprocal, so the slope is $\frac{5}{3}$

The equation of our line tangent to the circle at the point (5, 0) is $y = \frac{5}{3}x + b$

Now substitute in the point (5, 0) to solve for b

$0 = \frac{5}{3}(5) + b\\0 = \frac{25}{3} + b\\b = -\frac{25}{3}$

Therefore, the equation of the line tangent to the circle is

$y = \frac{5}{3}x - \frac{25}{3}$

Step-by-step explanation:

6 0

2 years ago

If a and b are two angles in standard position in Quadrant I, find cos(a+b) for the given function values. sin a=15/17and cos b=

tensa zangetsu [6.8K]

The value of $cos(a+b)$ for the angles $a$ and $b$ in standard position in the first quadrant is $-\frac{36}{85}$

We need to find the value of $cos(a+b)$ . To proceed, we need to use the compound angle formula

<h3>Cosine of a sum of two angles</h3>

The cosine of the sum of two angles $a$ and $b$ is given below

$cos(a+b)=cos(a)cos(b)-sin(a)sin(b)$

We are given

$sin(a)=\dfrac{15}{17}\\\\cos(b)=\dfrac{3}{5}$

We need to find $sin(b)$ and $cos(a)$ , using the identity

$sin^2(\theta)+cos^2(\theta)=1$

<h3>Find sin(b)</h3>

To find $sin(b)$ , note that

$sin^2(b)+cos^2(b)=1\\\\\implies sin(b)=\sqrt{1-cos^2(b)}$

substituting $\frac{3}{5}$ for $cos(b)$ in the identity, we get

$sin(b)=\sqrt{1-cos^2(b)}\\\\=\sqrt{1-\left(\dfrac{3}{5}\right)^2}=\dfrac{4}{5}$

<h3>Find cos(a)</h3>

To find $cos(a)$ , note that

$sin^2(a)+cos^2(a)=1\\\\\implies cos(a)=\sqrt{1-sin^2(a)}$

substituting $\frac{15}{17}$ for $sin(a)$ in the identity, we get

$cos(a)=\sqrt{1-sin^2(a)}\\\\=\sqrt{1-\left(\dfrac{15}{17}\right)^2}=\dfrac{8}{17}$

<h3>Find the value of cos(a+b)</h3>

We can now make use of the formula

$cos(a+b)=cos(a)cos(b)-sin(a)sin(b)$

to find $cos(a+b)$ .

$cos(a+b)=cos(a)cos(b)-sin(a)sin(b)\\\\=\dfrac{8}{17}\cdot\dfrac{3}{5}-\dfrac{15}{17}\cdot\dfrac{4}{5}=-\dfrac{36}{85}$

Learn more about sine and cosine of compound angles here brainly.com/question/24305408

8 0

1 year ago