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Sergeu [11.5K]
3 years ago
9

I need help ASAP please

Mathematics
1 answer:
RSB [31]3 years ago
4 0

Answer:

5:10

6 (-2,0)

7 (-5,6)

8 (5,3)

9 No, ab=8 CD=6

Step-by-step explanation:

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Combine the like terms to create an equivalent expression.<br><br> 7k-k+19
Harlamova29_29 [7]

Answer:

6k +19

Step-by-step explanation:

7k-k+19

Combine like terms

7k-k = 6k

The expression becomes 6k +19

6 0
3 years ago
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Two bags of cereal are packed in a box. The total weight of the box and the two bags of cereal is 58.00 ounces. One bag of cerea
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Answer:

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6 0
2 years ago
Suppose xy=−4 and dy/dt=−3. Find dx/dt when x=−1.
user100 [1]
When x=-1: \quad (-1)y=-4\qquad\to\qquad y=4\)

Ok that gives us a little more information.
If we implicitly differentiate with respect to t, from the very start, then we can apply our product rule, ya?

x'y+xy'=0

The right side is zero, derivative of a constant is zero.
Where x' is dx/dt and y' is dy/dt.

From here, plug in all the stuff you know:
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and solve for x'.

Hope that helps!
4 0
3 years ago
Simplify by expressing fractional exponents instead of radicals
igomit [66]

Answer:

a^{\frac{1}{2}}b^{\frac{1}{2}}

Step-by-step explanation:

Given:

The expression in radical form is given as:

\sqrt{ab}

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We know that,

\sqrt a=a^{\frac{1}{2}}

Also, \sqrt{ab}=\sqrt a\times \sqrt b

Now, clubbing both the properties of square root function, we can rewrite the given expression as:

\sqrt{ab}=\sqrt a \times \sqrt b\\\\\sqrt{ab}=a^{\frac{1}{2}}\times b^{\frac{1}{2}}\\\\\therefore \sqrt{ab}=a^{\frac{1}{2}}b^{\frac{1}{2}}

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3 0
3 years ago
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pentagon [3]

Answer:

10 minutes

Step-by-step explanation:

This is because if u have both the faucet and drain on at the same time, it will fill the tub faster

5 0
3 years ago
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