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katrin2010 [14]
3 years ago
15

What is the square root of 879?

Mathematics
2 answers:
Ivahew [28]3 years ago
3 0
The answer would be 29.6479341607
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konstantin123 [22]3 years ago
3 0
About 29.6479 is your answer :)
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PLEASE HELP DUE SOON 60 POINTS, EASY WORK!
Sergio [31]

Answer:-2, 4, -4

Step-by-step explanation:

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2 years ago
Don't know how to express the value of X as any of those answer choices
Alekssandra [29.7K]

9514 1404 393

Answer:

  x = √(w(w+z))

Step-by-step explanation:

The idea with a right-triangle figure of this sort is that all of the triangles are similar. Here, x is the short side of ∆ABC, and the hypotenuse of ∆BDC. This suggests you want to write a similarity statement involving the short side and hypotenuse.

  BC/AC = DC/BC . . . . . short side/hypotenuse

  BC² = AC·DC . . . . . . cross multiply

  x² = (w+z)w . . . . . . substitute letter values

Taking the square root and rearranging to the form of the applicable answer choice, this is ...

  \boxed{x=\sqrt{w(w+z)}}

3 0
3 years ago
X − 3y if x = 3 and y = −2.
Korvikt [17]

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Step-by-step explanation:

x - 3y

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5 0
2 years ago
-7 (5y - 2u - 5)<br> Use the distributive property to remove parentheses
Montano1993 [528]
Times -7 by everything in the parentheses. so

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8 0
3 years ago
Which equation could be solved using this application of the quadratic formula?
Alex_Xolod [135]

Answer:

C. x^2 + 2x - 1 = 3

Step-by-step explanation:

The standard form of a quadratic equation is

ax^2 + bx + c = 0

We need to use the quadratic formula and the given expression to find the values of a, b, and c.

The quadratic formula is

x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Where the formula has -b, the problem has -2, so b = 2.

Now we have

ax^2 + 2x + c = 0

In the denominator, where the formula has 2a, the problem has 2(1), so a = 1.

Now we have

x^2 + 2x + c = 0

Inside the root, the quadratic formula has -4ac. the problem shows -4(1)(-4). Since we already know that a = 1, then c = -4.

Now we have

x^2 + 2x - 4 = 0

Let's look at choice A.

x^2 + 1 = 2x - 3

Subtract 2x from both sides. Add 3 to both sides.

x^2 - 2x + 4 = 0   <em>This is not it!</em>

Let's look at choice B.

x^2 - 2x - 1 = 3

Subtract 3 from both sides.

x^2 - 2x - 4 = 0     <em>This is not it!</em>

Let's look at choice C.

x^2 + 2x - 1 = 3

Subtract 3 from both sides.

x^2 + 2x - 4 = 0     <em>This is it!</em>

Answer: C. x^2 + 2x - 1 = 3

8 0
3 years ago
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