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nordsb [41]
1 year ago
9

15 points please help me ASAP

Mathematics
1 answer:
gayaneshka [121]1 year ago
6 0
  1. The distance between the means is equal to 4.
  2. The mean absolute deviation (MAD) for player A is equal to 2.
  3. The mean absolute deviation (MAD) for player B is equal to 2.
  4. Distance between the means = two (2) times the MAD.
  5. There is some overlap and the distance between the means is between 1 times the MAD and 5 times the MAD.

<h3>What is a number line?</h3>

A number line can be defined as a type of graph with a graduated straight line which contains both positive and negative numerical values that are placed at equal intervals along its length.

<h3>What is a line plot?</h3>

A line plot can be defined as a type of graph that is used to graphically represent a data set above a number line, while using crosses, dots, or any other mathematical symbol.

<h3>What is a mean?</h3>

A mean is also referred to as an average and it can be defined as a ratio of the sum of the total number in a data set (population) to the frequency of the data set.

Mathematically, the distance between the means of both players A and B is given by:

Distance = Mean of player B - Mean of player A

Distance = 10 - 6

Distance = 4.

The mean absolute deviation (MAD) for player A is given by:

MAD A = 1/11[2(3 - 6) + 2(4 - 6) + (5 - 6) + (6 - 6) + (7 - 6) + 2(8 - 6) + 2(9 - 6)]

MAD A = 1/11[2(3) + 2(2) + (1) + (0) + (1) + 2(2) + 2(3)]

MAD A = 1/11[6 + 4 + 1 + 0 + 1 + 4 + 6]

MAD A = 1/11 × [22]

MAD A = 22/11

MAD A = 2.

Also, the mean absolute deviation (MAD) for player B is given by:

MAD B = 1/11[2(7 - 10) + 2(8 - 10) + (9 - 10) + (10 - 10) + (11 - 10) + 2(12 - 10) + 2(13 - 10)]

MAD B = 1/11[2(3) + 2(2) + (1) + (0) + (1) + 2(2) + 2(3)]

MAD B = 1/11[6 + 4 + 1 + 0 + 1 + 4 + 6]

MAD B = 1/11 × [22]

MAD B = 22/11

MAD B = 2.

Therefore, distance between the means = two (2) times the MAD.

Distance = Means × MAD

4 = 2 × 2.

In conclusion, we can infer and logically deduce that there is some overlap and the distance between the means of both players A and B is between one (1) times the MAD and five (5) times the MAD.

Read more on line plot here: brainly.com/question/8989301

#SPJ1

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MATH HELP...PLz
PilotLPTM [1.2K]

a. 14, 18, 22, 26.... It is +4

b. 2,430, 7,290, 21,870..... It is x3

c. So it is going -2, -4, -6, -8 so the next one would be -10 which is -13 then -12 which is -25 and so on.

Hope this helps!


8 0
4 years ago
Help please its URGENT!!!!!!!!
Aneli [31]

This is a relation but not a function.

Functions must have that there is a unique y for a given x, which clearly doesn't work here because all lines of a given x have 2 y-values. However, it is a relation because there is a given set of points which are defined to be within the set of the ellipse (if it's defined which members of two sets, the range and domain, go together, then you have a relation)

4 0
3 years ago
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A frame is marked down by 22 percent from an original price of $14.50. What is the new price?
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7 0
3 years ago
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Please help this is important<br> -1.5x+12=2.5x-12
Anna35 [415]

Answer:

x = 6

Step-by-step explanation:

move all terms to the left:

-1.5x+12-(2.5x-12)=0

get rid of parentheses

-1.5x-2.5x+12+12=0

add all the numbers together, and all the variable.

-4x+24=0

move all terms containing x to the left, all other terms to the right

-4x=-24

x=-24/-4 - divide

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7 0
3 years ago
A triangular course for a canoe race is marked with buoys. The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg
balu736 [363]
<h2>The race is 1.2 miles long</h2>

Step-by-step explanation:

The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi.

\texttt{Length of first leg = }\frac{3}{10}miles\\\\\texttt{Length of second leg = }\frac{1}{2}miles\\\\\texttt{Length of third leg = }\frac{2}{5}miles

Now we need to find length of race

       \texttt{Total length = }\frac{3}{10}+\frac{1}{2}+\frac{2}{5}\\\\\texttt{Total length = }\frac{3}{10}+\frac{5}{10}+\frac{4}{10}\\\\\texttt{Total length = }\frac{3+5+4}{10}\\\\\texttt{Total length = }\frac{12}{10}\\\\\texttt{Total length = }1.2miles

The race is 1.2 miles long

7 0
3 years ago
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