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1 year ago

15 points please help me ASAP

Mathematics

1 answer:

gayaneshka [121]1 year ago

6 0

The distance between the means is equal to 4.
The mean absolute deviation (MAD) for player A is equal to 2.
The mean absolute deviation (MAD) for player B is equal to 2.
Distance between the means = two (2) times the MAD.
There is some overlap and the distance between the means is between 1 times the MAD and 5 times the MAD.

<h3>What is a number line?</h3>

A number line can be defined as a type of graph with a graduated straight line which contains both positive and negative numerical values that are placed at equal intervals along its length.

A line plot can be defined as a type of graph that is used to graphically represent a data set above a number line, while using crosses, dots, or any other mathematical symbol.

A mean is also referred to as an average and it can be defined as a ratio of the sum of the total number in a data set (population) to the frequency of the data set.

Mathematically, the distance between the means of both players A and B is given by:

Distance = Mean of player B - Mean of player A

Distance = 10 - 6

Distance = 4.

The mean absolute deviation (MAD) for player A is given by:

MAD A = 1/11[2(3 - 6) + 2(4 - 6) + (5 - 6) + (6 - 6) + (7 - 6) + 2(8 - 6) + 2(9 - 6)]

MAD A = 1/11[2(3) + 2(2) + (1) + (0) + (1) + 2(2) + 2(3)]

MAD A = 1/11[6 + 4 + 1 + 0 + 1 + 4 + 6]

MAD A = 1/11 × [22]

MAD A = 22/11

MAD A = 2.

Also, the mean absolute deviation (MAD) for player B is given by:

MAD B = 1/11[2(7 - 10) + 2(8 - 10) + (9 - 10) + (10 - 10) + (11 - 10) + 2(12 - 10) + 2(13 - 10)]

MAD B = 1/11[2(3) + 2(2) + (1) + (0) + (1) + 2(2) + 2(3)]

MAD B = 1/11[6 + 4 + 1 + 0 + 1 + 4 + 6]

MAD B = 1/11 × [22]

MAD B = 22/11

MAD B = 2.

Therefore, distance between the means = two (2) times the MAD.

Distance = Means × MAD

4 = 2 × 2.

In conclusion, we can infer and logically deduce that there is some overlap and the distance between the means of both players A and B is between one (1) times the MAD and five (5) times the MAD.

Read more on line plot here: brainly.com/question/8989301

#SPJ1

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→ The fourth number in the sequence is: " 23 " .

_____________________________________

Explanation:

To solve:

" x + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 110 " ;

in which:

"x" = The first number in these sequence;

"(x + 1 )" = the second number in the sequence;

"(x + 2)" = the third number in the sequence;

"(x + 3)" = the fourth number in the sequence;

"(x + 4)" = the fifth number in the sequence;

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Solve for the "fourth number in the sequence" ; or: "(x + 3)" ;

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Given: " x + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 110 " ;

↔ " x + x + 1 + x + 2 + x + 3 + x + 4 = 110 " ;

→ Solve for "x" ;

→ then, solve for "(x + 3)" ;

→ which is the fourth number in this sequence;

_____________________________________

→ " x + x + 1 + x + 2 + x + 3 + x + 4= 110 " ;

"5x + 1 + 2 + 3 + 4= 110 " ;

" 5x + 10 = 110 " ;

Solve for "x" :

Subtract "10" from EACH SIDE of the equation; as follows:

" 5x + 10 - 10 = 110 - 10 " ;

to get :

" 5x = 100 " ;

Now, divide EACH SIDE of the equation by "5" ;

to isolate "x" on one side of the equation; & to solve for "x" ; as follows:

5x / 5 = 100 / 5 ;

to get:

" x = 20 " .

_____________________________________

Now, to find the fourth number in the sequence:

→ " (x + 3) " ;

→ Substitute "20" for "x" ;

" x + 3 = 20 + 3 = 23" ;

_____________________________________

The answer is: " 23 " .

The fourth number in the sequence is: " 23 " .

_____________________________________

Let us check our work:

If there are five "5" numbers in the sequence, and "23" is the "fourth number" , then: "24" is the "fifth number" .

As such: "22" is the "third number" ; "21" is the "second number" ; and "20" is the "first number" . Is this consistent with: "x = 20" as the "first number" ? Yes!

Thus, "20 + 21 + 22 + 23 + 25 = ? 110 ? ? ;

→ 20 + 21 = 41 ;

→ 41 + 22 = 63 ;

→ 63 + 23 = 86 ;

→ 86 + 24 = 110 . Yes!

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Hope this answer is helpful!

Best wishes in your academic pursuits—

and within the "Brainly" community!

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