Answer:
t(s) is in rejection zone then we reject H₀.
Bad weather indeed make apples weight decrease
Step-by-step explanation:
Normal Distribution
population mean μ₀ = 9.5 ou
sample size = n = 16 then we should apply t-student table
degree of fredom df = n - 1 df = 16 - 1 df = 15
1.-Test hypothesis
H₀ null hypothesis μ₀ = 9.5
Hₐ alternative hypothesis μ₀ < 9.5
One left tail-test
2.-Confidence level 95 %
α = 0,05 and df = 15 from t-student table we get t(c) = - 1.761
3.-Compute t(s)
t(s) = [ μ - μ₀ ] /√s/n t(s) = (9.32 - 9.5 )* √16 / 0.18
t(s) = - 0.18*√16 / 0.18
t(s) = - 4
4.-Compare t(s) and t(c)
t(s) < t(c) -4 < - 1.761
Then t(s) is in the rejection zone.
5.- Decision
t(s) is in rejection zone then we reject H₀.
Farmer conclude that bad weather make apples weight decrease
X=0,<span>3 i think. hope this helps
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U believe the answer is no, I believe this because eight 9 oz. bags is 72 oubces and both of them make less than that in 10 minutes. Machine A would make 42.5 oz in 10 minutes and Machine B would make 45 oz in 10 minutes.
C
1yd^2 = 9ft^2
_____yd^2 = 2700ft^2
2700 / 9 = 300 yd^2
Answer:
$2215.35
Step-by-step explanation:
27.35*75=2051.25
27.35*1.5=41.025
41.025*4=164.1
164.1+2051.25=2215.35
