Answer: 1) Vertex: (6, -2) Focus: (6, -7/4) Directrix: y = -9/4
2) Vertex: (-2, -1) Focus: (-7/4, -1) Directrix: x = -9/4
<u>Step-by-step explanation:</u>
Rewrite the equation in vertex format y = a(x - h)² + k or x = a(y - k)² + h by completing the square. Divide the b-value by 2 and square it - add that value to both sides of the equation.
- (h, k) is the vertex
- p is the distance from the vertex to the focus
- -p is the distance from the vertex to the directrix

1) y = x² - 12x + 34


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2) x = y² + 2y - 1


8 : 6 ...add 7 yellow and it becomes 15:6 when reduced = 5:2
So 90^2+90^2=c^2
8100+8100=c^2
16200=c^2
C= ~127.28
Integration by parts will help here. Letting

and

, you end up with

and

. Now


For the remaining integral, setting

gives

, so

Putting everything together, you end up with
It would be B because eaxh section either repeats itself or is close to repeating its previous part