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DENIUS [597]
4 years ago
10

Is ab perpendicular to cd ? Explain.

Mathematics
1 answer:
Afina-wow [57]4 years ago
4 0
We know that
if two lines are perpendicular
then
the slopes 
m1*m2=-1

step 1
find the slope AB
A (0,2)
B (-3,-3)
m=(y2-y1)/(x2-x1)-----> m=(-3-2)/(-3-0)-----> m=-5/-3----> m1=5/3

step 2
find the slope CD
C (-4,1)
D (0,-2)
m=(y2-y1)/(x2-x1)-----> m=(-2-1)/(0+4)-----> m=--3/4----> m2=-3/4

step 3
multiply mi*m2
(5/3)*(-3/4)-----> -15/12
so
15/12 is not -1
therefore
 AB is not perpendicular to CD
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X+y-z=5 -x-4y-8z=6 3x+5y-4z=-20
Juli2301 [7.4K]

Answer:

x = 24.48, y = -15.52, z = 3.95 to the nearest hundredth.

Step-by-step explanation:

 x+y-z=5             (a)

-x-4y-8z=6          (b)

3x+5y-4z=-20      (c)

Adding equations a and b:

-3y - 9z = 11       (d)

Now multiply equation b by 3:

-3x - 12y - 24z = 18        (e)

Adding  c and e:

-7y - 28z = -2      (f)  Multiply by 3 to give (g)

-3y - 9z = 11         (b)   Multiply by  -7 to give (h)

-21y - 84z = -6     (g)

21y + 63z = -77    (h)    Adding g and h:

-21z = - 83

z =  3.952

and y is found bt substituting in equation d:

-3y - 9(3.952) = 11

y = ( 11 + 9(3.952) / -3

= -15.52.

Now find x by substituting for y an z in equation a:

x - 15.52 - 3.952 = 5

x = 5 + 15.52 + 3.952

= 24.476.

3 0
3 years ago
En el estante de un negocio hay 2 tipos de tarros de la misma mermelada y marca. El tarro más alto tiene el doble de altura que
Ipatiy [6.2K]

Answer:

tarro corto

Step-by-step explanation:

Aquí tenemos que comprar el frasco que tiene el menor costo por volumen.

h_1 = Altura del frasco corto

h_2 = La altura del frasco alto es el doble que el del frasco corto. = 2h_1

d_1 = Diámetro del frasco corto

d_2 = El diámetro del frasco alto es la mitad del frasco corto = \dfrac{1}{2}d_1

El volumen de un cilindro es \pi \dfrac{d^2}{4}h

La razón de los volúmenes de los frascos es

\dfrac{V_1}{V_2}=\dfrac{\pi\dfrac{d_1^2}{4}h_1}{\pi\dfrac{d_2^2}{4}h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{d_2^2h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{(\dfrac{1}{2}d_1)^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{\dfrac{1}{4}d_1^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{1}{\dfrac{1}{2}}\\\Rightarrow \dfrac{V_1}{V_2}=2\\\Rightarrow V_1=2V_2

El costo del frasco corto por unidad de volumen es

\dfrac{8000}{V_1}=\dfrac{8000}{2V_2}=\dfrac{4000}{V_2}

El costo del frasco alto por unidad de volumen es

\dfrac{4500}{V_2}=\dfrac{4500}{V_2}

\dfrac{4000}{V_2}

Entonces, el costo del frasco corto por unidad de volumen es menor que el costo por unidad de volumen del frasco alto.

Por lo tanto, deberíamos tomar el frasco corto.

5 0
3 years ago
Mal spends 7 hours in school each day. Her lunch period is 1 hour long, and she spends a
Alex787 [66]

Answer:

z = 5*(1/2)

z = 5/10

---

time switching classes:

w = 7/10

---

y - 6x - z - w = 0

6x = y - z - w

x = (y - z - w)/6

x = (76/10 - 5/10 - 7/10)/6

x = (76 - 5 - 7)/(10*6)

x = (64)/(10*6)

x = (2*2*2*2*2*2)/(2*5*2*3)

x = (2*2*2*2)/(5*3)

x = 16/15

x = 1.0666666666

---

check:

y = 7 + 3/5

y = 7.6

z = 1/2

z = 0.5

w = 7/10

w = 0.7

y - 6x - z - w = 0

6x = y - z - w

x = (y - z - w)/6

x = (7.6 - 0.5 - 0.7)/6

x = 1.0666666666

---

answer:

z = 5*(1/2)

z = 5/10

---

time switching classes:

w = 7/10

---

y - 6x - z - w = 0

6x = y - z - w

x = (y - z - w)/6

x = (76/10 - 5/10 - 7/10)/6

x = (76 - 5 - 7)/(10*6)

x = (64)/(10*6)

x = (2*2*2*2*2*2)/(2*5*2*3)

x = (2*2*2*2)/(5*3)

x = 16/15

x = 1.0666666666

---

check:

y = 7 + 3/5

y = 7.6

z = 1/2

z = 0.5

w = 7/10

w = 0.7

y - 6x - z - w = 0

6x = y - z - w

x = (y - z - w)/6

x = (7.6 - 0.5 - 0.7)/6

x = 1.0666666666

---

answer:

each class is 1.07 hours

Step-by-step explanation:

8 0
3 years ago
Which of the following statements describe the system ?​
algol [13]

Answer:

one solution

Step-by-step explanation:

here, we want to select the correct option

From the system, we have two values of y

Equating the y-values

3x + 2 = -2x - 1

What this mean is that there is only a particular point where this solution will work and as such, the system has one solution

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3 years ago
A quality control engineer is testing the battery life of a new smartphone. The company is advertising that the
DIA [1.3K]

The question requires stating the Null and Alternative hypothesis for the scenario described :

Answer:

H0 : μ = 24

H1 : μ < 24

Step-by-step explanation:

The claim or hypothesis to be tested in a statistical problem or analysis is the alternative hypothesis. This is usually the opposite of the Null hypothesis which is the usually the initial truth until there is significant evidence provided using statistical test to prove otherwise.

The null hypothesis, H0 in the scenario above is :

H0 : μ = 24 ( average battery life is 24 hours)

The alternative hypothesis is the claim, that is. The mean battery life not up to 24 hours ;

H1 : μ < 24

4 0
3 years ago
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