For the whole thing including the other point it would be [-6, 6] but just for f it should be [6]
Answer: 30 minutes
How: 45 minutes divided by 15 math problems equal 3 minutes per math problem. 3 minutes per math problem times 10 math problems equals 30 minutes on 10 math problems.
45/15=3
3*10=30
1. solve for X and y using both equations to find the point they cross in
−x − y = −5
y = x + 1
Plug in y into first equation
-x-(x+1)=-5
-x-x-1=-5
-2x-1=-5
+1 both sides
-2x=-4
÷-2 both sides
x=2 solve for y
y=2+1
y=3
(2,3)
2. you can set them equal to each other so 2x+4=3x+1
Answer:
0.1587
Step-by-step explanation:
Let X be the commuting time for the student. We know that 
. Then, the normal probability density function for the random variable X is given by
![f(x) = \frac{1}{\sqrt{2\pi(5)^{2}}}\exp[-\frac{(x-\mu)^{2}}{2(5)^{2}}]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%7B2%5Cpi%285%29%5E%7B2%7D%7D%7D%5Cexp%5B-%5Cfrac%7B%28x-%5Cmu%29%5E%7B2%7D%7D%7B2%285%29%5E%7B2%7D%7D%5D)
. We are seeking the probability P(X>35) because the student leaves home at 8:25 A.M., we want to know the probability that the student will arrive at the college campus later than 9 A.M. and between 8:25 A.M. and 9 A.M. there are 35 minutes of difference. So,
= 0.1587
To find this probability you can use either a table from a book or a programming language. We have used the R statistical programming language an the instruction pnorm(35, mean = 30, sd = 5, lower.tail = F)
Answer:
3 × 5 ^ n
Step-by-step explanation:
since the series is exponential, the ratio between adjacent terms is 5.
nth term of geometric/exponential series is given by:
nth term = first term × (ratio)^(n-1)
= 15 × 5^ (n-1)
= 15 × 5^n × 5^-1
= 3× 5^n
