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skad [1K]
1 year ago
5

Which process is a squeezing motion of the circular layer of smooth muscle in the small intestine?

Biology
1 answer:
Over [174]1 year ago
4 0

Segmentation is a squeezing motion of the circular layer of smooth muscle in the small intestine.

<h3>What is segmentation in the small intestine?</h3>

Segmentation, which mostly affects the small intestine, is made up of localized contractions of the Gastro-Intestinal tract's circular muscle. These contractions separate out little portions of the intestine, allowing their contents to move back and forth while being continuously divided, broken up, and mixed.

Our intestines' circular muscles contract during segmentation to churn food back and forth, rather like a washing machine. This churning helps break down food into tiny bits for digestion by allowing it to mix with gastric secretions in the intestines. By bringing chyme into contact with the intestinal walls during segmentation, the technique also helps to increase absorption.

Learn more about segmentation here:

brainly.com/question/2133778

#SPJ4

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3 years ago
Una solución de 0.204 M de NaOH seutiliza para neutralizar 50 mL de una solución de H3PO4. Si se necesitaron 16.4 mL de la soluc
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Answer: 0.05 M

Explanation:

Para responder esta pregunta, hay que tener en cuenta la Ley de Conservación de la Masa. <u>La misma indica que en una reacción química en un sistema cerrado, la masa total de las moléculas que participan permanece constante.</u> Esto significa que la masa utilizada en los reactivos es la misma que la masa de los productos generados.

En este problema, se cuenta con una solución de NaOH (hidróxido de sodio) tiene una molaridad de 0.204 (siendo la molaridad el número de moles por litro de solución) y se utilizan 16.4 mL de dicha solución para agregarla a 50 mL de una solución de H3PO4 (ácido fosfórico).

Entonces, ya que la masa de ambas soluciones no se pierde, podemos utilizar la ecuación de la Ley de Conservación de la Masa:

Concentración inicial x Volumen inicial = Concentración final x Volumen final.

Concentración inicial: 0.204 M

Volumen inicial: 16.4 mL

Concentración final: ?

Volumen final: 50 mL + 16.4 mL = 66.4 mL

Reemplazamos los valores en la ecuación:

0.204 M x 16.4 mL = Concentración final x 66.4 mL

La molaridad de la solución de H3PO4 es de 0.05 M.

7 0
3 years ago
The energy lost during transformation is always in the form of:
levacccp [35]

Answer:

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When energy is transformed from one form to another, or moved from one place to another, or from one system to another there is energy loss. This means that when energy is converted to a different form, some of the input energy is turned into a highly disordered form of energy, like heat.

Hope this helped! :^)

8 0
2 years ago
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