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2 years ago

a LOT of points (80pts) I will give brainlest to the right answer please help me with this 3 questions :(

Biology

2 answers:

kogti [31]2 years ago

7 0

Explanation: wow thats fresh got shutdown for no reason am i right

777dan777 [17]2 years ago

4 0

Answers:

#1:

The process that takes place in the stroma in both sunlight and darkness is the Calvin cycle. In sunlight and darkness the Calvin cycle produces a light dependent reaction which then produces ATP and NADPH. Even in darkness the process will still be able to undergo completion. If it has been dark for too long there will not be enough ATP and NADPH to continue sugar production.

#2:

Pyruvate: If there is any oxygen molecules produced in glycolysis will be passed to the Kreb cycle but when there isnt enough oxegen the transport chain wont run which mean fermentation will occur since the NADH molecules have nowhere to go.

NADH: Will go into electron transport.

ATP: Stores energy for a period of time.

#3:

Mitosis and cytokinesis both go through cell division and during mitosis chromatis divides into daughter cells meanwhile cytokinesis has one cell split into two. Without cytokinesis, mitiosis would still happen but only create two nucli in one cell and if cytokinesis happens the cell would die.

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the birth rate must exceed the death rate
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Thus, options B and D are correct.

More on population growth can be found here: brainly.com/question/18415071

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2 years ago

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Answer:

Explanation:

Mendel's law of independent assortment state that two different genes assort independently in gamete formation.

To reach this conclusion, one has to do a dihybrid cross. This means that two genes responsible for different traits need to be analyzed at the same time.

1) Starting with a parental generation of a cross between two pure lines (homozygous for both genes) with different traits, a plant with yellow and round seeds (YYRR) and another with green and wrinkled seeds (yyrr). The F1 will be phenotypically homogeneous (yellow and round), and genotypically heterozygous (YyRr).

2) If the individuals from the F1 are crossed with one another, we have to do a Punnett Square to determine the phenotypic ratio of the F2.

If the genes assort independently, the F1 individuals will produce their different gametes with the same probability. Each possible gamete will appear in a 1/4 proportion: YR, Yr, yR, yr.
The 9:3:3:1 ratio is a result of analyzing the possible phenotypes that result from the dihybrid cross.

See the attached image for an illustration of the crosses in each generation and the Punnett Square.

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