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dlinn [17]
1 year ago
12

If the work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb, how much work is needed to stretch it 18 in.

beyond its natural length
Mathematics
1 answer:
Blababa [14]1 year ago
5 0

If the work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb,then the work that is needed to stretch it 18 inches beyond its natural length is 81 ft.lb.

Given that work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb.

We are required to find the work that is needed to stretch 18 inches beyond its natural length.

Multiplication is basically finding out the product of two or more numbers.

Work required to stretch the spring 2 feet beyond its natural length=9 ft. lb.

So, to find the work that is required to stretch the spring 18 feet beyond its natural length, we have to multiply 9 with 9 which will give us 81. So the work required is 81 ft.lb.

Hence if the work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb,then the work that is needed to stretch it 18 inches beyond its natural length is 81 ft.-lb.

Learn more about multiplication at brainly.com/question/10873737

#SPJ4

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Given:

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To find:

The limit of the function by using direct substitution.

Solution:

We have,

\lim_{x\to 3}(x^2+8x-2)

Applying limit, we get

\lim_{x\to 3}(x^2+8x-2)=(3)^2+8(3)-2

\lim_{x\to 3}(x^2+8x-2)=9+24-2

\lim_{x\to 3}(x^2+8x-2)=33-2

\lim_{x\to 3}(x^2+8x-2)=31

Therefore, the correct option is D.

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3 years ago
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Read 2 more answers
3. Consider the sequence,-8, -5, -2, 1, ...
Naddik [55]

Answer:

a) a_n=3\,n-11

b) a_{20}=49

c) term number 17 is the one that gives a value of 40

Step-by-step explanation:

a)

The sequence seems to be arithmetic, and with common difference d = 3.

Notice that when you add 3 units to the first term (-80, you get :

-8 + 3 = -5

and then -5 + 3 = -2 which is the third term.

Then, we can use the general form for the nth term of an arithmetic sequence to find its simplified form:

a_n=a_1+(n-1)\,d

That in our case would give:

a_n=-8+(n-1)\,(3)\\a_n=-8+3\,n-3\\a_n=3n-11

b)

Therefore, the term number 20 can be calculated from it:

a_{20}=3\,(20)-11=60-11=49

c) in order to find which term renders 20, we use the general form we found in step a):

a_n=3\,n-11\\40=3\,n-11\\40+11=3\,n\\51=3\,n\\n=\frac{51}{3} =17

so term number 17 is the one that renders a value of 40

5 0
2 years ago
A bottle contains 568 millilitres of milk Jack pours out half a litre how much milk is left?
pantera1 [17]

Answer:

68 mL

Step-by-step explanation:

1 liter = 1000 mL

1/2 of 1000 mL = 500 ml

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3 0
2 years ago
A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate
Lyrx [107]

Answer:

Therefore the rate change of height is  \frac{1}{\pi} m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

\frac{dV}{dt}=4 \ m^3/s

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is V=\pi r^2 h

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\therefore V= 4\pi h

Differentiating with respect to t.

\frac{dV}{dt}=4\pi \frac{dh}{dt}

Putting the value \frac{dV}{dt}

\Rightarrow 4\pi \frac{dh}{dt}=4

\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}

\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}

The rate change of height does not depend on the height.

Therefore the rate change of height is  \frac{1}{\pi} m/s.

3 0
2 years ago
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