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MA_775_DIABLO [31]
2 years ago
10

9) Complete the function table using the equation

Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
3 0

Answer:

I don't understand the arrangement of the "table."  I'll assume the question wants to know the values of b as a increase from 2 to 6.

Step-by-step explanation:

The resulting table is attached.

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Can someone please help me with this ​
Readme [11.4K]

Answer:

7) 28.8 in

8) 80.6 mm

9) 68.3 cm

(All answers to the nearest tenth)

Step-by-step explanation:

7) The traingle is a right-angled triangle since the 4 angles of a rectangle are right angles.

Applying Pythagoras' Theorem,

x²= 16² +24²

x²= 832

x= √832

x= 28.8 in (nearest tenth)

8) Applying Pythagoras' Theorem,

x² +40²= 90²

x²= 8100 -1600

x²= 6500

x= 80.6 mm (nearest tenth)

9) See the attached picture for better understanding.

1st picture shows the simplified diagram of the question, indicating where line x lies in the rectangular prism.

Now, if we cut the prism into half diagonally so that we obtain 2 equal triangular prism, we would obtain 2 prisms that look like the one drawn in picture 2.

Now zoom in to the blue face of the prism, we would get a triangle as shown in picture 3.

Let's find the value of y.

Applying Pythagoras' Theorem,

y²= 40² +54²

y²= 4516

y= √4516

Look at picture 2 again at focus at the pink shaded triangle. It has been re-drawn in picture 4.

Now we know that y= √4516.

Applying Pythagoras' Theorem,

x²= (√4515)² +12²

x²= 4660

x= √4660

x= 68.3 cm (nearest tenth)

3 0
3 years ago
Find the value of tan θ for the angle shown. A line is drawn from the origin through the point square root of thirty-three comma
Bogdan [553]
If you draw this triangle on a graph as described, tan theta is -4(square root)33/33

8 0
3 years ago
Read 2 more answers
Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2 ( using the property (ab)^m=a^m.b^m )

=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

6 0
3 years ago
Read 2 more answers
In a cinema, there are eight seats in a row. Four of the seats in one row are occupied. What fraction of seats are available in
Anarel [89]

Answer:

<h2>\frac{1}{2}</h2>

Step-by-step explanation:

Given,

There are 8 seats in a row.

There are 8 seats in a row.4 seats are occupied.

Available seats = 8 - 4 = 4 seats

Fraction of seats available:

\frac{number \: of \: seats \: available}{total \: number \: of \: seats}

=  \frac{4}{8}

Reduce the fraction with GCF 4

=  \frac{1}{2}

Hope this helps..

Best regards!!

4 0
3 years ago
Read 2 more answers
Write an equation to represent the following description "fourteen less than 8 times a number is -11
Serggg [28]

Answer:

(8 * x) -14 = -11

Step-by-step explanation:

* = multiply sign (i didnt want to put "x" as the multiply sign since "x" is already being used) ( mightve confused you with 2 "x"s in the parenthesis.

x = the number that is missing being multiplied by 8

I put "8" multiplied by "x" in parenthesis since you do parenthesis first in an equation.

6 0
3 years ago
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