2 years ago

Twice a number divided by five

Mathematics

1 answer:

Hatshy [7]2 years ago

7 0

Twice a number divided by 5 is expressed known as 2x/5. Equations are expressions separated by an equal sign.

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The area of a rectangle is equal to its length times its width. If the area of a rectangle is 4x +20 which options could be the

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Answer:

The required option are

Length = 4 and width = x+5

Length = 2 and width = 2x+10

Step-by-step explanation:

Area of the rectangle = Length × width

Given

Area = 4x+20

Factoring out the common terms

Area = 4x + 4(5)

Area = 4(x+5)

Length = 4 and width = x+5

This can also be written as

Area = 2(2x+10)

Length = 2 and width =2x+10

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Answer:

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umka21 [38]

Answer:

$F=\frac{K Q1Q2}{d^2} \\$

Step-by-step explanation:

According to coulombs law "the force of attraction or repulsion between two charges Q1 and Q2 in a given medium is directly proportional to the product of their charges and inversely proportional to the square of the distance separating them"

$F=\frac{K Q1Q2}{d^2} \\$

where

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A rectangle has a height of 6k3 and a width of 2k2 + 4k +5.

Trava [24]

Answer: $12k^5+24k^4+30k^3$

Step-by-step explanation:

Given : The height of the rectangle = $6k^3$

The width of the rectangle = $2k^2+4k+5$

Formula : Area = height x width

Therefore , the area of triangle in terms of polynomial will be :

$6k^3\times( 2k^2+4k+5)\\\\= 6k^3(2k^2)+6k^3(4k)+6k^3(5)\ \ [\text{Using Distributive property}]\\\\=12k^{3+2}+24k^{3+1}+30k^3\ \ [\text{Using exponents rule}:\ a^n\times a^m=a^{n+m}]\\\\=12k^5+24k^4+30k^3$

Hence, the area of the entire rectangle = $12k^5+24k^4+30k^3$

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