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erik [133]
1 year ago
11

Twice a number divided by five

Mathematics
1 answer:
Hatshy [7]1 year ago
7 0

Twice a number divided by 5 is expressed known as 2x/5. Equations are expressions separated by an equal sign.

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Find an ordered pair to represent a in the equation<br> a=2b+c if b=(6,3) and c=(-4,8)
zaharov [31]

Answer:

The ordered pair to represent a in the equation a=2b+c if b=(6,3) and c=(-4,8) is: a=(8,14)

Step-by-step explanation:

b=(6,3)

c=(-4,8)

a=2b+c

Replacing b and c in the equation above:

a=2(6,3)+(-4,8)

Multiplying:

a=(2*6,2*3)+(-4,8)

a=(12,6)+(-4,8)

Adding:

a=(12+(-4),6+8)

a=(12-4,14)

a=(8,14)

8 0
4 years ago
I need help with this it’s saying the “blank” Method would be the best for solving this system of equations
aleksandrvk [35]

Answer:

-12+4y=x..............1

6(-12+4y)+4y=8

-72+24y+4y=8

28y=80

y=3.33

-12+4(3.33)=x

1.32=x

5 0
3 years ago
Limit definition for slope of the graph, equation of tangent line point for<br> f(x)=2x^2 at x=(-1)
Tems11 [23]

The slope of the tangent line to f at x=-1 is given by the derivative of f at that point:

f'(-1)=\displaystyle\lim_{x\to-1}\frac{f(x)-f(-1)}{x-(-1)}=\lim_{x\to-1}\frac{2x^2-2}{x+1}

Factorize the numerator:

2x^2-2=2(x^2-1)=2(x-1)(x+1)

We have x approaching -1; in particular, this means x\neq-1, so that

\dfrac{2x^2-2}{x+1}=\dfrac{2(x-1)(x+1)}{x+1}=2(x-1)

Then

f'(-1)=\displaystyle\lim_{x\to-1}\frac{2x^2-2}{x+1}=\lim_{x\to-1}2(x-1)=2(-1-1)=-4

and the tangent line's equation is

y-f(-1)=f'(-1)(x-(-1))\implies y-4x-2

6 0
3 years ago
Please help need answer. NO LINKS
nikklg [1K]

Answer:

Answer choice C) 3a-3

Step-by-step explanation:

Your perimeter is of (10a-6). The first step would be multiply 2a by 2 since you have to sides. Which would give you to 4a. Next you will have to subtract 4a from (10a-6). This would give you 6a-6. Finally divide by two and you will get 3a-3.

7 0
3 years ago
To
yanalaym [24]

Answer:

I think it's 56 students have a gadgets

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2 years ago
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