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Nutka1998 [239]
3 years ago
13

Brainliest + points! Please HELP and explain

Mathematics
1 answer:
Papessa [141]3 years ago
5 0

Answer:

D

Step-by-step explanation:

The hypotenuse is x and the adjacent side to the given angle is 54

cos20° = \frac{adjacent}{hypotenuse} = \frac{54}{x}

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castortr0y [4]

Answer:

It would be $371.39

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3 years ago
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In rectangle KLMN, KM = 10x+24 and KN = 64 find x
pishuonlain [190]
Hi there, I don't know if I am right but I will try to solve this, 10x+24=64, subtract 24 from both sides, 10x+24-24=64-24=10x=40, divide both sides by 10, 10x/10=40/10, x=4
7 0
3 years ago
Can anyone help me with this problem
Rama09 [41]

9514 1404 393

Answer:

  8. A = {Delaware, New Jersey, Pennsylvania}

  9. |B| = 3

Step-by-step explanation:

8. Dates prior to 1 Jan 1788 are those in 1787. The three states admitted in 1787 are listed as Delaware, Pennsylvania, New Jersey. It is usually convenient to list elements of a set in lexicographical order:

  A = {Delaware, New Jersey, Pennsylvania}

__

9. The months June and July appear 3 separate times on the list, so there would be 3 elements in the set B.

  |B| = 3

3 0
3 years ago
Ellie’s bird feeder is shaped like a cone with a height of 24 in. and a radius of 3 in. Packages of bird seed are cylindrical an
love history [14]
The volume of seeds in the package must be equal to the volume of the feeder in order to fill it completely. The volume of the conic feeder is given by:
V(f) = (πr²h)/3
And volume of the cylindrical package is given by:
V(p) = πr²h
Equating the two and substituting values:
(π x 3² x 24)/3 = π x 6² x h
h = 2 inches
3 0
3 years ago
Please help? I’m super lost...
babunello [35]

Answer:

Step-by-step explanation:

In all of these problems, the key is to remember that you can undo a trig function by taking the inverse of that function.  Watch and see.

a.  sin2\theta =-\frac{\sqrt{3} }{2}

Take the inverse sin of both sides.  When you do that, you are left with just 2theta on the left.  That's why you do this.

sin^{-1}(sin2\theta)=sin^{-1}(-\frac{\sqrt{3} }{2} )

This simplifies to

2\theta=sin^{-1}(-\frac{\sqrt{3} }{2} )

We look to the unit circle to see which values of theta give us a sin of -square root of 3 over 2.  Those are:

2\theta =\frac{5\pi }{6} and

2\theta=\frac{7\pi }{6}

Divide both sides by 2 in both of those equations to get that values of theta are:

\theta=\frac{5\pi }{12},\frac{7\pi }{12}

b.  tan(7a)=1

Take the inverse tangent of both sides:

tan^{-1}(tan(7a))=tan^{-1}(1)

Taking the inverse tangent of the tangent on the left leaves us with just 7a.  This simplifies to

7a=tan^{-1}(1)

We look to the unit circle to find which values of <em>a</em> give us a tangent of 1.  They are:

7\alpha =\frac{5\pi }{4},7\alpha =\frac{\pi }{4}

Dibide each of those equations by 7 to find that the values of alpha are:

\alpha =\frac{5\pi}{28},\frac{\pi}{28}

c.  cos(3\beta)=\frac{1}{2}

Take the inverse cosine of each side.  The inverse cosine and cosine undo each other, leaving us with just 3beta on the left, just like in the previous problems.  That simplifies to:

3\beta=cos^{-1}(\frac{1}{2})

We look to the unit circle to find the values of beta that give us the cosine of 1/2 and those are:

3\beta =\frac{\pi}{6},3\beta  =\frac{5\pi}{6}

Divide each of those by 3 to find the values of beta are:

\beta =\frac{\pi }{18} ,\frac{5\pi}{18}

d.  sec3\alpha =-2

Let's rewrite this in terms of a trig ratio that we are a bit more familiar with:

\frac{1}{cos(3\alpha) } =\frac{-2}{1}

We are going to simplify this even further by flipping both fraction upside down to make it easier to solve:

cos(3\alpha)=-\frac{1}{2}

Now we will take the inverse cos of each side (same as above):

3\alpha =cos^{-1}(-\frac{1}{2} )

We look to the unit circle one last time to find the values of alpha that give us a cosine of -1/2:

3\alpha =\frac{7\pi}{6},3\alpha  =\frac{11\pi}{6}

Dividing both of those equations by 3 gives us

\alpha =\frac{7\pi}{18},\frac{11\pi}{18}

And we're done!!!

8 0
3 years ago
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