Question

G542x is another cftr allele. If a female heterozygous for g542x bears a child fathered by a male heterozygous for the δf508 allele, what is the probability that the child would be homozygous for the g542x allele, given that neither parent has cf?.

Answer 1

Probability that the child would be homozygous for the g542x allele 0.00

why the probability is nil?

• The kid cannot be homozygous for the G542X gene since only the mother has it; the father, on the other hand, has a mutant dF508 allele and so cannot pass on a copy of mutant G542X = never homozygous recessive child.

• A kid must have the G542X allele from both parents in order to be homozygous for the G542X allele. Because only the mother possesses the G542X gene, the child's chances of being homozygous for the G542X allele are 0.00

When offspring show a blend of the parents traits one allele is dominant over the other?

• At the point when one allele is predominant over another, posterity show a mix of guardians' qualities.
• The heterozygous aggregate in complete predominance is tracked in the middle of between two homozygous aggregates. A heterozygous individual showcases qualities of the two guardians in the event of codominance.

To learn more about hetrozygous from the given link

brainly.com/question/1626661

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