Answer:
(B) HEK cells exposed to the most hypotonic conditions will display the greatest degree of AQP5 membrane localization, allowing water to flow into the cells.
Explanation:
The function of AQP5 (an aquaporin) is to allow the water to move into or out of the cell down the concentration gradient. When placed in hypotonic solutions, the internal environment of HEK cells will be hypertonic. Water always moves from hypotonic (higher water concentration) to hypertonic (lower water concentration) solution.
Hence, the HEK cells exposed to the hypotonic conditions will localize AQP5 in their membranes to allow the water to move from out hypotonic conditions to the inner hypertonic environment.
During the Silurian Period, simple PLANTS began too grow on land and in damp trees
Answer:
FfPp
Explanation:
If we take the two traits to be separate alleles, we can make flowers F (F is dominant; f is recessive) and pollen as P (P is dominant; p is recessive). So a pea plant with white flowers (recessive) and long pollen (dominant) will have the genotype ffPp or ffPP (because one dominant allele will express a dominant phenotype).
For this question, we will assume that the wild type (red flowers and long pollen) is homozygous, meaning it contains two dominant alleles.
If the wild type (FFPP) is crossed with the plant with white flowers and short pollen (ffpp), we can make a table illustrating the crosses. However, because there is only one possible gamete that each parent can form (FP and fp), we can assume that the F1 progeny will have identical genotypes, which can be expressed as FfPp (because combining the gamete from the wild type and the other parent can only give one phenotype).