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grin007 [14]
1 year ago
15

X-1/x-2+x+3/x-4=2/(x-2).(4-x)

Mathematics
1 answer:
Varvara68 [4.7K]1 year ago
3 0

The given equation x-1/x-2+x+3/x-4=2/(x-2).(4-x) is correct. the answer is proved.

According to the statement

we have given that the equation and we have to prove that the given answer is a correct answer for those equivalent equation.

So, The given expression are:

\frac{x-1}{x-2} +\frac{x+3}{x-4} = \frac{2}{(x-2).(4-x)}

And we have to prove the answer.

So, For this

\frac{x-1}{x-2} +\frac{x+3}{x-4}

\frac{({x-1}) ({x-4}) +({x+3})({x-2})} {(x-2) (x-4)}

Then the equation become

\frac{x^{2} -4x -x +4 + x^{2} -2x + 3x -6 }{(x-2) (x-4)}

Now solve it then

2x^{2} - 4x -2 / (x-2) (x-4)

Now take 2 common from answer then equation become

\frac{x-1}{x-2} +\frac{x+3}{x-4} = \frac{2}{(x-2).(4-x)}

Hence proved.

So, The given equation x-1/x-2+x+3/x-4=2/(x-2).(4-x) is correct. the answer is proved.

Learn more about equations here

brainly.com/question/2972832

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Step-by-step explanation:

Let L the total length of the piece of wire, where L-x and x are the perimeters of the greater and lesser squares. All lengths are measured in centimeters. Since squares have four sides of equal length, the side lengths for the greater and lesser squares are \frac{L-x}{4} and \frac{x}{4}. From statement we find that the sum of the areas of the two squares (A), measured in square centimeters, is represented by the following expression:

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A = \frac{L^{2}-2\cdot L\cdot x +x^{2}}{16} + \frac{x^{2}}{16}

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If we know that L = 76\,cm and A = 205\,cm^{2 }, then the length of the shorter part of the wire is:

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By the Quadratic Formula, we determine the roots associated with the polynomial:

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3 years ago
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