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salantis [7]
1 year ago
8

Advantages of using tidal power include _____. no air pollution tides are predictable low environmental impact all of these

Physics
2 answers:
Katena32 [7]1 year ago
7 0

Answer:

short answer: ALL OF THESE

Explanation:

lana66690 [7]1 year ago
3 0

Advantages of using tidal power include no air pollution, no air pollution and low environmental impact.

<h3>What is Tidal Power?</h3>

The rush of ocean waters during tide changes is what generates tidal energy. A renewable energy source is tidal energy.

In places with a wide tidal range—the distance between high tide and low tide—engineers devised methods to harness tidal movement to generate power during the 20th century. Each technique turns tidal energy into electricity using specialised generators.

Production of tidal energy is still in its infancy. So yet, hardly much electricity has been generated. There aren't many commercial-scale tidal power facilities in operation worldwide. The first was at France's La Rance. The Sihwa Lake Tidal Power Station in South Korea is the biggest facility. There are very few places in the United States where tidal energy might be generated at a competitive price and no tidal plants. Russia, Canada, France, England, and China have the most potential for using this kind of energy.

Advantages of using tidal power include no air pollution, no air pollution and low environmental impact.

to learn more about tidal power go to - brainly.com/question/22892730

#SPJ4

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6 0
3 years ago
A 75kg man climbs the stairs to the fifth floor of a building. A total hieght of 16m. His potential energy has increased by
yKpoI14uk [10]

Answer:

11760 joules

Explanation:

Given

Mass (m) = 75kg

Height (h) = 16m

Required

Determine the increment in potential energy (PE)

This is calculated as thus:

PE = mgh

Where g = 9.8m/s²

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3 years ago
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6 0
3 years ago
On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a golf club improvised from a tool. The free-f
aliya0001 [1]

Answer:

15.3 s and 332 m

Explanation:

With the launch of projectiles expressions we can solve this problem, with the acceleration of the moon

    gm = 1/6 ge

    gm = 1/6  9.8 m/s² = 1.63 m/s²

We calculate the range

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We will calculate the time of flight,

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0 = Vo sin  t – ½  g t2

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0= 12.5 t –  0.815 t2

We solve the equation

0= t ( 12.5 -0.815 t)

 t=0 s

t= 15.3 s

The value of zero corresponds to the departure point and the flight time is 15.3 s

Let's calculate the reach on earth

R2 = 25² sin (2 30) / 9.8

R2 = 55.2 m

R/R2 = 332/55.2

R/R2 = 6

Therefore the ball travels a distance six times greater on the moon than on Earth

5 0
3 years ago
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