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3 years ago

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Ardi and lei are both travelling by train. Ardi’s train travels 70km in 35 minutes. Lei’s train travels 585km. It leaves at 9:05

and arrives at 13:35. Work out the difference in Km/h between the average speed of there trains

1 answer:

LuckyWell [14K]3 years ago

8 0

Answer:47.14km/h

Step-by-step explanation:

585÷3 and 1/2=167.14km/h

70÷35/60=120km/h

167.14-120=47.14km/h

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3 years ago

ABC and EDC are straight lines. EA is parallel to DB. EC = 8.1 cm. DC = 5.4 cm. DB = 2.6 cm. (a) Work out the length of AE. cm (

harkovskaia [24]

By applying the knowledge of similar triangles, the lengths of AE and AB are:

a. $\mathbf{AE = 3.9 $ cm}\\\\$

b. $\mathbf{AB = 2.05 $ cm} \\\\$

<em>See the image in the attachment for the referred diagram.</em>

<em />

The two triangles, triangle AEC and triangle BDC are similar triangles.
Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.

<em>This implies that</em>:

AC/BC = EC/DC = AE/DB

<em><u>Given:</u></em>

$EC = 8.1 $ cm\\\\DC = 5.4 $ cm\\\\DB = 2.6 cm\\\\AC = 6.15 $ cm$

<u>a. </u><u>Find the length of </u><u>AE</u><u>:</u>

EC/DC = AE/DB

Plug in the values

$\frac{8.1}{5.4} = \frac{AE}{2.6}$

Cross multiply

$5.4 \times AE = 8.1 \times 2.6\\\\5.4 \times AE = 21.06$

Divide both sides by 5.4

$AE = \frac{21.06}{5.4} = 3.9 $ cm$

<u>b. </u><u>Find the length of </u><u>AB:</u>

$AB = AC - BC$

AC = 6.15 cm

To find BC, use AC/BC = EC/DC.

Plug in the values

$\frac{6.15}{BC} = \frac{8.1}{5.4}$

Cross multiply

$BC \times 8.1 = 6.15 \times 5.4\\\\BC = \frac{6.15 \times 5.4}{8.1} \\\\BC = 4.1$

Thus:

$AB = AC - BC$

Substitute

$AB = 6.15 - 4.1\\\\AB = 2.05 $ cm$

Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:

a. $\mathbf{AE = 3.9 $ cm}\\\\$

b. $\mathbf{AB = 2.05 $ cm} \\\\$

Learn more here:

brainly.com/question/14327552

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