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aniked [119]
3 years ago
11

Ardi and lei are both travelling by train. Ardi’s train travels 70km in 35 minutes. Lei’s train travels 585km. It leaves at 9:05

and arrives at 13:35. Work out the difference in Km/h between the average speed of there trains
Mathematics
1 answer:
LuckyWell [14K]3 years ago
8 0

Answer:47.14km/h

Step-by-step explanation:

585÷3 and 1/2=167.14km/h

70÷35/60=120km/h

167.14-120=47.14km/h

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Tasya [4]
Use the Pythagorean Theorem to find the length of the side marked "x."
x^2 + (10 mi)^2 = (13 mi)^2.  Thus, x^2 + 100 mi^2 = 169 mi^2.
Next, x^2= (169-100) mi^2, or x^2 = 69 mi^2.  Find the positive square root of both sides of this equation.  What is it?
3 0
3 years ago
Please answer this question correctly I need it today please show work
oksano4ka [1.4K]

Answer:

1: C(n) = 2.50 + 16n

2: $66.50

Step-by-step explanation:

Part 1

Each ticket costs $16 per person. If tickets for n persons were purchased, the total cost would be 16n.

There is also a one-time service fee of $2.50 that must be paid. Thus, for n tickets the total cost is

C(n) = 2.50 + 16n

Part 2

For n = 4, the expression evaluates to

C(4) = 2.50 + 16 (4) = $66.50

7 0
3 years ago
A boat traveled 308 miles each way downstream and back. The trip downstream took 11 hours. The trip back took 22 hours. Find the
photoshop1234 [79]

Answer:

speed of boat is 12 miles per hour and the speed of current is 9 miles per hour

Step-by-step explanation:

8 0
3 years ago
Use Gaussian elimination to write each system in triangular form
Feliz [49]

Answer:

To see the steps to the diagonal form see the step-by-step explanation. The solution to the system is x =  -\frac{1}{9}, y= -\frac{1}{9}, z= \frac{4}{9} and w = \frac{7}{9}

Step-by-step explanation:

Gauss elimination method consists in reducing the matrix to a upper triangular one by using three different types of row operations (this is why the method is also called row reduction method). The three elementary row operations are:

  1. Swapping two rows
  2. Multiplying a row by a nonzero number
  3. Adding a multiple of one row to another row

To solve the system using the Gauss elimination method we need to write the augmented matrix of the system. For the given system, this matrix is:

\left[\begin{array}{cccc|c}1 & 1 & 1 & 1 & 1 \\1 & 1 & 0 & -1 & -1 \\-1 & 1 & 1 & 2 & 2 \\1 & 2 & -1 & 1 & 0\end{array}\right]

For this matrix we need to perform the following row operations:

  • R_2 - 1 R_1 \rightarrow R_2 (multiply 1 row by 1 and subtract it from 2 row)
  • R_3 + 1 R_1 \rightarrow R_3 (multiply 1 row by 1 and add it to 3 row)
  • R_4 - 1 R_1 \rightarrow R_4 (multiply 1 row by 1 and subtract it from 4 row)
  • R_2 \leftrightarrow R_3 (interchange the 2 and 3 rows)
  • R_2 / 2 \rightarrow R_2 (divide the 2 row by 2)
  • R_1 - 1 R_2 \rightarrow R_1 (multiply 2 row by 1 and subtract it from 1 row)
  • R_4 - 1 R_2 \rightarrow R_4 (multiply 2 row by 1 and subtract it from 4 row)
  • R_3 \cdot ( -1) \rightarrow R_3 (multiply the 3 row by -1)
  • R_2 - 1 R_3 \rightarrow R_2 (multiply 3 row by 1 and subtract it from 2 row)
  • R_4 + 3 R_3 \rightarrow R_4 (multiply 3 row by 3 and add it to 4 row)
  • R_4 / 4.5 \rightarrow R_4 (divide the 4 row by 4.5)

After this step, the system has an upper triangular form

The triangular matrix looks like:

\left[\begin{array}{cccc|c}1 & 0 & 0 & -0.5 & -0.5  \\0 & 1 & 0 & -0.5 & -0.5\\0 & 0 & 1 & 2 &  2 \\0 & 0 & 0 & 1 &  \frac{7}{9}\end{array}\right]

If you later perform the following operations you can find the solution to the system.

  • R_1 + 0.5 R_4 \rightarrow R_1 (multiply 4 row by 0.5 and add it to 1 row)
  • R_2 + 0.5 R_4 \rightarrow R_2 (multiply 4 row by 0.5 and add it to 2 row)
  • R_3 - 2 R_4 \rightarrow R_3(multiply 4 row by 2 and subtract it from 3 row)

After this operations, the matrix should look like:

\left[\begin{array}{cccc|c}1 & 0 & 0 & 0 & -\frac{1}{9}  \\0 & 1 & 0 & 0 &   -\frac{1}{9}\\0 & 0 & 1 & 0 &  \frac{4}{9} \\0 & 0 & 0 & 1 &  \frac{7}{9}\end{array}\right]

Thus, the solution is:

x =  -\frac{1}{9}, y= -\frac{1}{9}, z= \frac{4}{9} and w = \frac{7}{9}

7 0
3 years ago
How many times do you apply the distributive property in this example: 2(x + 5) – 3(2x + 7) ?
Brut [27]

Answer:

Hi there!

Your answer is two times.

Step-by-step explanation:

The distributive property is multiplying the coefficient in front of parentheses into the parentheses. You have two sets of parentheses both with a coefficient that needs to be distributed.

The first time you use it is on 2(x+5), distributing the 2.

The second time you use it is on the -3(2x+7), distributing the -3

Please let me know if you have questions :)

6 0
3 years ago
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