We are given
arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103
so, first term is 124
u(1)= 124
now, we can find common difference
now, we can find kth term
now, we can plug values
and we get
u(k) must be negative
so,
now, we can solve for k
so, it's closest integer value is
..............Answer
Answer:
The answer is c!
Step-by-step explanation:
A = ( 1 +r/n)^nth
or something, use .0585
Hello from MrBillDoesMath!
Answer:
-15
Discussion:
We are asked to evaulate:
abs(3) + ( -2 (3)^2) = => as abs(3) = 3
3 + (-2*9) =
3 - 18 =
-15
Thank you,
MrB
If you were born in 1997 how old are you in 2017
A/ you are 20 years old
